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Jlenok [28]
2 years ago
10

When you do this please show the work

Mathematics
1 answer:
mart [117]2 years ago
7 0

Answer:

2) \displaystyle -9a^3b^5

1) \displaystyle \frac{x^8}{3}

Step-by-step explanation:

2) \displaystyle \frac{(27a^3b^3)(-2ab^4)}{6ab^2} \Rightarrow \frac{(3ab)^3(-2ab^4)}{6ab^2} \\ \\ \boxed{-9a^3b^5} \rightarrow \frac{-54a^4b^7}{6ab^2}

1) \displaystyle \frac{16x^{10}y^2}{48x^2y^2} \Rightarrow \frac{(-4x^5y)^2}{48x^2y^2} \\ \\ \boxed{\frac{x^8}{3}}

The Quotient-to-Power Rule states that whenever you are dividng like-terms, you <em>keep</em> the coefficients and deduct the exponents.

I am joyous to assist you at any time.

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