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Anna71 [15]
2 years ago
5

Why did the melon jump into the lake

Mathematics
2 answers:
jek_recluse [69]2 years ago
7 0

Answer:

<h2>It wanted to be a water melon.</h2>

Step-by-step explanation:

<h3>Also this is the og answer, <u>the other person that commented stole my answer</u>. That's my friends and we were on call together while I said the answer. That person is a thief and we are no longer friends. Please give me the full credit and rathe their answer a low score. Feeling very angry and betrayed. </h3>
malfutka [58]2 years ago
7 0

Answer:

It wanted to be a water melon

Step-by-step explanation:

this is the answer because a lake is full of water and it jumped in the lake to be a water melon and not just a melon (and i am not taking the other persons answer btw)

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Answer:

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Step-by-step explanation:

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Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


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