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2 years ago

Why did the melon jump into the lake

Mathematics

2 answers:

jek_recluse [69]2 years ago

7 0

Answer:

<h2>It wanted to be a water melon.</h2>

Step-by-step explanation:

<h3>Also this is the og answer, <u>the other person that commented stole my answer</u>. That's my friends and we were on call together while I said the answer. That person is a thief and we are no longer friends. Please give me the full credit and rathe their answer a low score. Feeling very angry and betrayed. </h3>

malfutka [58]2 years ago

7 0

Answer:

It wanted to be a water melon

Step-by-step explanation:

this is the answer because a lake is full of water and it jumped in the lake to be a water melon and not just a melon (and i am not taking the other persons answer btw)

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Louisa cuts 7 peices of yarn.

defon

Answer:

i need more details

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Factorise 6x - 3y + 9<br> Please explain how to do this

wel

Answer:

3(2x-y+3)

you factor every number in the math question.

5 0

2 years ago

Using the following information = Universal set = {2,3,4,5,6,7,8,9,12,13,14,16,20,22,56). Subset A = {9,12,13,20,22,56); Subset

Cloud [144]

$\dfrac{2}{5},\dfrac{13}{15},\dfrac{3}{5},\dfrac{1}{5},\dfrac{1}{5}$

step-by-step explanation:

The intersection of two sets A and B, denoted by A ∩ B, is the set containing all elements of A that also belong to B.

The union (denoted by ∪) of a collection of sets is the set of all elements in the collection.

$P(s)$ of a set $s$ is defined as ratio of number of elements in $s$ to the number of elements in $universal set$

given $Universalset=$ $\{$ $\text{2,3,4,5,6,7,8,9,12,13,14,16,20,22,56}$ $\}$

given $A=\{9,12,13,20,22,56\}$ and $H=\{4,5,8,9,16,22\}$

and $C=\{1,4,20,22,56\}$

For Question A:

$A$ ∩ $H$ = $\{9,12,13,20,22,56\}$ ∩ $\{4,5,8,9,16,22\}$

= $\{9,22}\}$

( $A$ ∩ $H$ )∪ $C$ = $\{9,22}\}$ ∪ $C=\{1,4,20,22,56\}$ = $\{1,4,9,20,22,56\}$

$p((A$ ∩ $H)$ ∪ $C)$ = $\frac{6}{15}=\frac{2}{5}$

For Question B:

$H$ ∩ $C$ = $\{4,22\}$

$p(H$ ∩ $C)$ '= $\frac{15-2}{15}=\frac{13}{15}$

For Question C:

$p(H)$ '= $\frac{15-6}{15}=\frac{3}{5}$

For Question D:

$C$ \ $H$ = $\{1,20,56\}$

$p(C$ \ $H)$ = $\frac{3}{15}=\frac{1}{5}$

For Question E:

$A$ \ $C$ = $\{9,12,13\}$

$p(A$ \ $C)$ = $\frac{3}{15}=\frac{1}{5}$

7 0

3 years ago

all of the following expressions have the same result, except A.-7/8 ÷ (-1/4) B. ( -7/8)×(-4) C. (8/7)×(1/4) D. 7/8/1/4

yan [13]

Answer

Step-by-step explanation:

3 0

3 years ago

Help me with this problem I've been working on it for a while now and just can't figure it out

Serggg [28]

1. Write out the problem: 3x+12/3

2. Find the common factor: 3(x+4)/3

3. Cancel out the threes.

4. Once you cancel them out you get: x+4

Hope I could help. Have a great day!:-)))

7 0

3 years ago