Distance between two points is
Root of X2 - X1 squared + Y2 - Y1 squared
So here X2 is 0 X1 is 0 as the origin is 0,0
Root of Y2-Y1 squared is what we are left with
Root of -2- -3 squared
Root of 1 squared
Root of 1
Which is 1
Distance is 1
Answer: (32-4) divided by 4 = g
Step-by-step explanation:
Answer:
54.5 Sq. cm
Step-by-step explanation:
<em>area of a right angled triangle = 1/ 2 × base × height </em>
(here, the base is 8 and height is 6)
= 1/ 2 × 6 × 8
= 4 × 6
<u>= 24 Sq. cm</u>
<em>area of a circle</em> =
r²
(r is the radius that is diameter/ 2, and the value of
is 3. 14)
= 3. 14.× (5)²
= 3.14 × 25
<u>= 78.5 Sq. cm</u>
area of the shaded region = area of Circle - area of triangle
= 78.5 - 24
<h3>= 54.5 Sq. cm</h3>
that is option 3
Answer:
a 8
Step-by-step explanation:
You are given two sides and the included angle. Since you don't have any side and the opposite angle, you must use the law of cosines.
![a^2 = b^2 + c^2 - 2bc\cos A](https://tex.z-dn.net/?f=%20a%5E2%20%3D%20b%5E2%20%2B%20c%5E2%20-%202bc%5Ccos%20A%20)
![a^2 = 5^2 + 11^2 - 2(5)(11)\cos 39^\circ](https://tex.z-dn.net/?f=%20a%5E2%20%3D%205%5E2%20%2B%2011%5E2%20-%202%285%29%2811%29%5Ccos%2039%5E%5Ccirc%20)
![a^2 = 25 + 121 - 110\cos 39^\circ](https://tex.z-dn.net/?f=%20a%5E2%20%3D%2025%20%2B%20121%20-%20110%5Ccos%2039%5E%5Ccirc%20)
![a^2 = 60.51](https://tex.z-dn.net/?f=%20a%5E2%20%3D%2060.51%20)
![a = 7.779](https://tex.z-dn.net/?f=%20a%20%3D%207.779%20)
Answer: a = 8 cm
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.