The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.
The given parameters;
- s(t) = -9t² + 103t + 403
- time interval (4.499, 4.5), and (4.5, 4.501)
The average velocity of the bottle rocket over the intervals is calculated as follows;
when the interval = [<em>4.499, 4.5</em>]
![s(4.499)= -9(4.499)^2 + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m](https://tex.z-dn.net/?f=s%284.499%29%3D%20-9%284.499%29%5E2%20%20%2B%20103%284.499%29%20%2B%20403%20%3D%20684.22%20%5C%20m%5C%5C%5C%5Cs%284.5%29%20%3D%20%20-9%284.5%29%5E2%20%20%2B%20103%284.5%29%20%2B%20403%20%3D%20684.25%20%5C%20m)
![v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B%5CDelta%20%5C%20s%7D%7B%5CDelta%20%5C%20t%7D%20%3D%20%5Cfrac%7B684.25%20-%20684.22%7D%7B4.5%20-%204.499%7D%20%3D%2030%20%5C%20m%2Fs)
when the interval = [<em>4.5, 4.501</em>]
![s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s](https://tex.z-dn.net/?f=s%284.5%29%20%3D%20-9%284.5%29%5E2%20%2B%20103%284.5%29%20%2B%20403%20%3D%20684.25%20%5C%20m%5C%5C%5C%5Cs%284.501%29%20%3D%20-9%284.501%29%5E2%20%2B%20103%284.501%29%20%2B%20403%20%3D684.27%20%5C%20m%5C%5C%5C%5Cv%3D%20%5Cfrac%7B684.27%20-%20684.25%7D%7B4.501-4.5%7D%20%5C%5C%5C%5Cv%20%3D%2020%20%5C%20m%2Fs)
The instantaneous velocity of the bottle rocket at time t=4.5;
![v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%20%5C%20s%28t%29%7D%7Bdt%7D%20%3D%20-18t%20%2B%20103%5C%5C%5C%5Cv%284.5%29%20%3D%20-18%284.5%29%20%2B%20103%5C%5C%5C%5Cv%284.5%29%20%3D%2022%20%5C%20m%2Fs)
Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.
Learn more here: brainly.com/question/25009886
D. First time freshmen, current students, and transfer students.
Answer:
Both are normal distributions but standard normal distribution is a particular case of Normal distribution when the mean is 0 and standard deviation or variance is 1. This makes Y a “Standard” distribution. So basically X is Normally distributed and Y is “Standard” normally distributed.
That would be B. Folkways. I'm guessing you're in Sociology as well :)
Answer:
civilization vs the wild natural law
Explanation:
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