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blsea [12.9K]
2 years ago
11

A triangle has an area of 42 cm2. The height of the triangle is 14 centimeters. What is the length of the base of the triangle.

Mathematics
1 answer:
pentagon [3]2 years ago
7 0

Answer:

6 centimeters

Step-by-step explanation:

Area of a triangle is   A = height x base / 2

So plug in what you know.

42 = (14 x b)/2  get rid of the 2 by multiplying both sides by 2 which gives:

84 = 14 x b       get rid of the 14 by dividing both sides by 14

b = 84/14

b=6 cm

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The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

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The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter
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Answer:

He must survey 123 adults.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Assume that a recent survey suggests that about 87​% of adults have heard of the brand.

This means that \pi = 0.87

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So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How many adults must he survey in order to be 90​% confident that his estimate is within five percentage points of the true population​ percentage?

This is n for which M = 0.05. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.05 = 1.645\sqrt{\frac{0.87*0.13}{n}}

0.05\sqrt{n} = 1.645\sqrt{0.87*0.13}

\sqrt{n} = \frac{1.645\sqrt{0.87*0.13}}{0.05}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.87*0.13}}{0.05})^2

n = 122.4

Rounding up:

He must survey 123 adults.

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3 years ago
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