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Aleksandr [31]
1 year ago
7

Solveeeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
Sauron [17]1 year ago
8 0

Answer:

A - The mean is the best representation because 99 is an outlier

Dovator [93]1 year ago
8 0

Answer:

A

Step-by-step explanatiothe

mean is the best representation over the past the 8 days  

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What is the value of n?
vitfil [10]
9(n+7) = 18(n+1)
9n + 63 = 18n + 18
9n = 45
  n = 5

answer
n = 5
3 0
3 years ago
An insured's roof cost $4,000 when installed 5 years ago. It has been damaged by hail and must be replaced. The new roof will co
hoa [83]

Answer:

ACV=$4,500

Step-by-step explanation:

We have that the actual cash value (ACV) is defined as:

ACV=\dfrac{R\times(E-C)}{E}

Where:

ACV = actual cash value

R = replacement cost or purchase price of the item

E = expected life of the item

C = current life of the item

Then we have R=$6,000, C=5years, and to find the expected life of the item we can use the depreciating of the roof, then if the roof is depreciating $200 each year we just need to divide $4,000 by $200 to find the expected life of the roof:

\dfrac{4,000}{200}=20

Then the espected life of the roof is 20 years, with this result we have all the data, then:

ACV=\dfrac{\$6,000\times (20-5)}{20}=\dfrac{\$6,000\times (15)}{20}=\dfrac{\$90,000}{20}=\$4,500

Then the ACV is $4,500

5 0
3 years ago
The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f
Temka [501]
Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct
8 0
3 years ago
Find the volume of a sphere with the diameter of 4
givi [52]
d=4 \Rightarrow r=2\\V=\dfrac{4}{3}\pi r^3\\
V=\dfrac{4}{3}\pi \cdot2^3\\
V=\dfrac{4}{3}\pi \cdot8\\
V=\dfrac{32}{3} \pi

5 0
3 years ago
What is the second step in the​ construction?
MrMuchimi

Answer:

To draw the perpendicular bisector of any line segment, the compass opening should be the kept constant at any value a little more than half the length of the line segment. Then the compass point should be kept on one end and arcs drawn above and below and then keeping the same compass opening the same as mentioned before, the compass point should be placed on the other end and the arcs should be drawn above and below the segment touching the previous arcs.

Thus, out of the given options, the first option best suits the next step Herberto should take.

Step-by-step explanation:

5 0
3 years ago
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