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julia-pushkina [17]
2 years ago
14

James buys 7 baseballs and 1 bat.

Mathematics
2 answers:
Blizzard [7]2 years ago
8 0
66.50 - 42.00 = 24.50

24.50 / 7 = 3.50
Jlenok [28]2 years ago
7 0

Answer:

$3.50

Step-by-step explanation:

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Lizzy and Ella sold 10 boxes of cookies for $55.50. How much does each box of cookies cost? Show all your work and explain how y
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Solve for d when 2x-2yd=y+xd ...?
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3 0
2 years ago
Testing to see if there is evidence that the proportion of US citizens who can name the capital city of Canada is greater than 0
klemol [59]

Answer:

b) B and D and c) A and C

Step-by-step explanation:

The hypotheses would be:

H_0: p =0.75\\H_a: p >0.75

(Right tailed test at 5% level)

Sample proportions are

Sample              A                 B                C                 D

Success            31               34               27               38

Proportion p     0.775         0.85            0.675          0.95

Std error

(sqrtpq/n)          0.066        0.056          0.074          0.034

p diff

p-0.75               0.025        0.10             - 0.075        0.20

Z stat                  

p diff/SE            0.0757       1.77                 1.01          5.80

p value               0.469       0.038             0.156       0.000001

we find that p value is more smaller than alpha, the more accurate the alternate hypothesis.

b) Only B and D provide against the null.  Because p <0.05

c) A and C provide no evidence for the alternative because p >0.05

8 0
3 years ago
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
2 years ago
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