This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units
<h3>First expression:</h3>
Factor 44 out of 44r+352.
44(r+8)
<h3>
Second expression:</h3>
Factor −16 out of 448−16b+112c.
−16(b−7c−28)
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Answer:
z=12
Step-by-step explanation:
5+7=12
For this you want to solve a 2-step equation
0.5x+4.2=5.9
subtract 4.2 from the left and right sides
then divide on the left and right sides
x=3.4 (option B)
Hey!
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a. Has a vertical axis of symmetry.
Answers: B and D
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b. Has a horizontal axis of symmetry.
Answers: D and E
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c. Passes through exactly one quadrant.
Answers: A and D
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d. Passes through all 4 quadrants.
Answers: B and F
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Hope This Helped! Good Luck!
