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2 years ago

Brainliest if it is right

Mathematics

2 answers:

inessss [21]2 years ago

6 0

Answer:

1. 31.4 cm

2. 15.7 cm

Step-by-step explanation:

kobusy [5.1K]2 years ago

3 0

Answer:

1. 31.4 cm

2. 15.7 cm

Step-by-step explanation:

Circumference = π X Diameter

Diameter for blue circle = 10 cm

Circumference = 31.4159265 = 31.4 cm

Diameter for orange circle = 5 cm

Circumference = 15.7079633 = 15.7 cm

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Karen has 120. if she saves 24 per week, how many weeks will it take her to have a total of 312

son4ous [18]

Answer:

13 weeks

Step-by-step explanation:

312/24=13

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4 years ago

What is the volume of the hemisphere? 583.2cm^3cm 3 291.6cm^3cm 3 6882.3cm^3cm 3 3441.1cm^3cm 3 Item at position 3

Sveta_85 [38]

Answer:

See Explanation

Step-by-step explanation:

The question has missing details; as the radius or an attachment of the hemisphere is not given.

However, I'll solve on a general terms.

The volume of a hemisphere is: $V = \frac{2}{3}\pi r^3$

Take for instance

$r = 14.9cm$

The volume becomes:

$V = \frac{2}{3} * 3.142 * 14.9^3$

$V = \frac{2 * 3.142 * 14.9^3}{3}$

$V = \frac{20787.151516}{3}$

$V = 6929.051cm^3$

<em>So, all you need to do is plug in the value of radius in the formula.</em>

7 0

3 years ago

ASAP Help!!!!!

Nina [5.8K]

19/6

it has to be a fraction

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3 years ago

Solve the matrix and prove that it is equal 0

Art [367]

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

$\tt{ {A}^{T} = \begin{bmatrix} 2 & - 4 \\ 4 & 3 \\ \end{bmatrix}}$

$\underline{ \underline { \text{To \: Find}}} :$

$\sf{ {A}^{2} - 5A+ 22I= 0}$

$\underline{ \underline{ \text{Solution}}} :$

The new matrix obtained from a given matrix by interchanging it's rows and columns is called the transposition of matrix. It is denoted by $\sf{ {A}^{T}}$ . Again , Interchange it's rows and columns in order to find ' A '.

$\tt{A = \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix}}$

Now , LEFT HAND SIDE ( L.H.S )

$\tt{ {A}^{2} - 5A+ 22I}$

Here, I refers to identity matrix. A diagonal matrix in which all the elements of leading diagonal are 1 ( unit ) is called unit or identity matrix.

⟼ $\begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} \times \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} - 5 \times \begin{bmatrix} 2 & 4 \\ - 4 & 3 \\ \end{bmatrix} + 22 \times \begin{bmatrix} 1 & 0 \\ 0 & 1\\ \end{bmatrix}$

⟼ $\begin{bmatrix} 2 \times 2 + 4 \times ( - 4)& 2 \times 4 + 4 \times 3 \\ - 4 \times 2 + 3 \times ( - 4) & - 4 \times 4 + 3 \times 3 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20& 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$

⟼ $\begin{bmatrix} 4 + ( - 16) & 8 + 12 \\ - 8 + ( - 12) & - 16 + 9 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$

⟼ $\begin{bmatrix} - 12 & 20\\ - 20& - 7 \\ \end{bmatrix} - \begin{bmatrix} 10 & 20 \\ - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 & 0 \\ 0 & 22 \\ \end{bmatrix}$