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STALIN [3.7K]
3 years ago
7

A. 7 B. 8 C.9 D. 6 FOR BRAINLIST!!

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

Answer:

It is going to be C.9 hope this help hopefully not late. :D

Step-by-step explanation:

Its like a train so (2x3)+8x(7x-2)= your answer but you can solve it in a calculator :D

tamaranim1 [39]3 years ago
8 0

Answer:

D. 7

Step-by-step explanation:

According to this problem, the sum of the angles is 90°. This means we're adding.

2x + 3x + 8 + 7x - 2 = 90.

To make this easier to solve, we can combine like terms.

2x + 3x + 7x = 12x.

The remaining numbers are 8 and -2.

8 + -2 = 6

Our final expression is:

12x + 6 = 90

First, subtract 90 from 6 and get 84.

Lastly, divide the difference (84) by 12.

12x = 84

84 / 12 = 7.

Therefore, the value of x is 7.

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Write 5 as a fraction with 5 in the denominator
Ivenika [448]
25/5 is a THE fraction
8 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]
matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

f(x)=ln(x)

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0
3 years ago
A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,
algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}

Where v_i is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is [0, \pi/2]. The critical  points of the function are those who make d'(\theta)=0:

d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}

d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...

The critical value inside the interval is \pi/4.

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft

The second step is to find the values of the function at the endpoints of the interval:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft

The biggest value of f is gived by \pi/4, therefore \pi/4 is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

4 0
3 years ago
I’m sorry I keep asking for help I’m not at my best self right now. Can you guys please help me again?
Semenov [28]

Answer:

which ones you want solved? all?

Step-by-step explanation:

7 0
2 years ago
You stand 100’ from the base of a tower. The tower is 1,058’ tall. What is the angle from where you are standing to the top of t
hodyreva [135]

Answer: 85°


Step-by-step explanation:

Trig functions are remembered by


SOD CAD TOA,


sin = opposite / distance, cos = adjacent / distance, and tan = opposite / adjacent.


Here we have the adjacent side = 100, opposite side = 1058. The tower would fall over if it weren't vertical, and we assume the area is flat and level. So tangent of the answer is 10.58.


We need the angle whose tangent is 10.58.

On Android calculator you swipe left to get the trig functions, tap INV, if RAD is showing tap it to change it to DEG, and tap tan⁻¹. Swipe right and you see tan⁻¹(. Enter 10.58 and the result shows 84.6005606. If it shows 1.47655833 tap the RAD in upper left to change to DEG.

8 0
3 years ago
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