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sattari [20]
2 years ago
10

The Oriental Pearl Tower in Shanghai, China, is a 468-meter high tower with 11 spheres along the tower. Two spheres are larger t

han the rest and house meeting areas, an observation deck, and a revolving restaurant. The lower of the two larger spheres has a radius of 25 meters, and the higher sphere has a radius of 22.5 meters. What is the approximate total volume of the two largest spheres on the Oriental Pearl Tower?
Mathematics
1 answer:
Alexeev081 [22]2 years ago
4 0

The approximate total volume of the two largest spheres on the Oriental Pearl Tower 113105.45 m³.

<h3 /><h3>How to find the volume of a sphere</h3>

The volume of the sphere is calculated as follows:

volume = 4 / 3 πr³

where

  • r = radius

The lower two larger spheres in the tower has a radius of 25 meters and 22.5 meters. Therefore, the total volume of the two largest sphere is as follows:

volume of lower sphere = 4 / 3 × 3.14 × 25³

volume of lower sphere = 196250 / 3

volume of lower sphere = 65416.6666667

volume of lower sphere = 65416.7 m³

volume of higher sphere = 4 / 3 × 3.14 × 22.5³

volume of higher sphere = 143066.25 / 3

volume of higher sphere = 47688.75

volume of higher sphere = 47688.8 m³

The approximate total volume = 65416.7 + 47688.8  = 113105.45 m³

learn more on sphere here: brainly.com/question/13833611

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Oksi-84 [34.3K]
19 145=0.422222222 or 0.422
8 0
3 years ago
): If (6x-3)(6x+3)=ax^2-b, what is the value of a? What is the value of b?
lesantik [10]
Answer: a = 36 and b = 9

Explanation:

(6x-3)(6x+3)

= 36x² - 18x - 18x - 9

= 36x² - 9



(6x-3)(6x+3) = ax² - b

36x² - 9 = ax² - b

a = 36 and b = 9

Hope it helps!
7 0
3 years ago
What is the greatest common factor of 150, 275 and 420
larisa [96]

Answer:

I believe the answer is 5!

Step-by-step explanation:

3 0
2 years ago
PLS HELP ILL GIVE BRAINLIEST
inysia [295]
<h3>Answer:   14x - 8</h3>

=======================================================

Explanation:

I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.

The equation is of the form ax^2+bx+c = 0

  • a = 12
  • b = -11
  • c = -5

This leads to...

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-11)\pm\sqrt{(-11)^2-4(12)(-5)}}{2(12)}\\\\x = \frac{11\pm\sqrt{361}}{24}\\\\x = \frac{11\pm19}{24}\\\\x = \frac{11+19}{24} \ \text{ or } \ x = \frac{11-19}{24}\\\\x = \frac{30}{24} \ \text{ or } \ x = \frac{-8}{24}\\\\x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}

Now use those roots to form these steps

x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}\\\\4x = 5 \ \text{ or } \ 3x = -1\\\\4x - 5 =0 \ \text{ or } \ 3x+1 = 0\\\\(4x-5)(3x+1) = 0

Refer to the zero product property for more info.

Therefore, the original expression factors fully to (4x-5)(3x+1)

Use the FOIL rule to expand it out and you should get 12x^2-11x-5 again.

----------------------------------------------

We did that factoring so we could find the side lengths of the rectangle.

I'm using the fact that area = length*width

  • L = length = 4x-5
  • W = width = 3x+1

The order of length and width doesn't matter.

From here, we can then compute the perimeter of the rectangle

P = 2(L+W)

P = 2(4x-5+3x+1)

P = 2(7x-4)

P = 14x - 8

6 0
2 years ago
Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000&#10;

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
2 years ago
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