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Lilit [14]
3 years ago
7

Liza buys 4 yards of fabric for $8.48. How much was the fabric per yard?

Mathematics
2 answers:
yarga [219]3 years ago
6 0
Answer:
The fabric per yard is 2.12
levacccp [35]3 years ago
5 0

Answer:

the fabric per yard was 2.12

Step-by-step explanation:

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Alicia will construct a rectangle that has a height of 4 units and an area of up to 48 square units. Which inequality represents
Nezavi [6.7K]

Answer:

b ≤ 12

Step-by-step explanation:

The area of the rectangle is given by length multiplied by breadth.

The area of the rectangle up to 48 units square means that it can be 48 or less than 48.

If the height given is taken as the width of the rectangle then we can find the base which will be the length of the rectangle.

Area = length * breadth

4units * base ≤ 48 units square

base ≤ 48 units square/4 units

base ≤ 12 units

b ≤ 12 units

4 0
3 years ago
Hey everyone! Please help me figure this out...
shepuryov [24]

Answer:

See below

Step-by-step explanation:

0.82=82/100=82%

22%=22/100=0.22

3/4=0.75=75/100=75%

0.8=0.80=80/100=80%

Hope this helps!

5 0
3 years ago
Read 2 more answers
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
What is the solution to the system of equations below? y = -3X+5 and y=4x-2 (1, 2) (1, –18) (–1, 8) (–1, –6)
Maurinko [17]

Answer:

(1, 2 )

Step-by-step explanation:

Given the 2 equations

y = - 3x + 5 → (1)

y = 4x - 2 → (2)

Substitute y = 4x - 2 into (1)

4x - 2 = - 3x + 5 ( add 3x to both sides )

7x - 2 = 5 ( add 2 to both sides )

7x = 7 ( divide both sides by 7 )

x = 1

Substitute x = 1 into (2) for corresponding value of y

y = (4 × 1) - 2 = 4 - 2 = 2

Solution is (1, 2 )

4 0
3 years ago
Read 2 more answers
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
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