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marta [7]
2 years ago
6

Find the mean, median, and mode of the data set. Round to the hundredths, if necessary. 29,300 24,350 32,400 15,100 14,200 21,95

0 27,450 29,400 15,200 35,050 16,050 11,500 13,050 11,500 11,600 11,100 21,450
Mathematics
1 answer:
Sav [38]2 years ago
3 0

The mean of the data is 20038.24, the median is 16050 while the number with the highest frequency is 11500

<h3>Mean, median, and mode of a dataset</h3>

Mean are known as averages, median is the middle value after rearrangement while the mode is the value with the highest frequency

Calculate the mean

Mean = sum of data/sample size

Given the data

29300, 24350, 32400, 15100, 14200, 21950, 27450, 29400, 15200, 35050, 16050, 11500, 13050, 11500, 11600, 11100, 21450

The mean of the data is 20038.24

For the median being the value at the middle, the median is 16050 while the number with the highest frequency is 11500

Learn more on mean, median and mode here: brainly.com/question/14532771

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suppose our school is having a talent show to raise money for new music supplies .you estimate that 200 students and 150 adults
solong [7]
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You can use x and y instead of s for student and a for adult.
Are the adults and students charged the same? If so then:
200x + 105x + 200 = 1,000

5 0
3 years ago
Read 2 more answers
ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12.
Naily [24]

Answer:

Explained below.

Step-by-step explanation:

(11)

Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

[(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z

Thus, the final expression is (-11x + y - 12z).

(12)

From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).

[(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5

Thus, the final expression is (7x² - y² - x + y + 5).

(13)

What should be subtracted from (x² – xy + y² – x + y + 3) to obtain (-x²+ 3y²- 4xy + 1)?

A=(x^{2} - xy + y^{2} - x + y + 3) - (-x^{2}+ 3y^{2}- 4xy + 1)\\=x^{2} - xy + y^{2} - x + y + 3 +x^{2}- 3y^{2}+ 4xy -1\\=2x^{2}-2y^{2}+3xy-x+y+2

Thus, the expression is (2x² - 2y² + 3xy - x + y + 2).

(14)

What should be added to (xy – 3yz + 4zx) to get (4xy – 3zx + 4yz + 7)?

A=(4xy-3zx + 4yz + 7)-(xy - 3yz + 4zx) \\=4xy-3zx + 4yz + 7 -xy + 3yz - 4zx\\=3xy-7zx+7yz+7

Thus, the expression is (3xy - 7zx + 7yz + 7).

(15)

How much is (x² − 2xy + 3y²) less than (2x² − 3y² + xy)?

A=(2x^{2} - 3y^{2} + xy)-(x^{2} - 2xy + 3y^{2})\\=2x^{2} - 3y^{2} + xy-x^{2} + 2xy - 3y^{2}\\=x^{2}-6y^{2}+3xy

Thus, the expression is (x² - 6y² + 3xy).

7 0
3 years ago
WILL GIVE BRAINLIEST IF CORRECT
SCORPION-xisa [38]

9514 1404 393

Answer:

  5544 square units

Step-by-step explanation:

Translation does not change the dimensions of the figure. The two figures together tell you the right triangle has a base of 154 units and a height of 72 units.

The area of a triangle is given by ...

  A = 1/2bh

  A = 1/2(154 units)(72 units) = 5544 square units

The areas of each of the triangles are 5544 square units.

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Answer: $ 2.55

Step-by-step explanation:

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wariber [46]

Answer:

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Step-by-step explanation:

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