All the y values would be 0, since it’s a horizontal line
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
-5n - 3 - 3 > 19
-5n - 6 > 19
+ 6 +6
-5n > 25
divide by -5 on each side
change signs since dividing by negative
N< -5
For graphing on the line, you will create an OPEN circle on -5 and sketch it to the left.
Answer:
Step-by-step explanation:
-6x²+15x+9=0
divide by -3
2x²-5x-3=0
2x²+x-6x-3=0
x(2x+1)-3(2x+1)=0
(2x+1)(x-3)=0
either x=-1/2
or x=3
