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Liula [17]
2 years ago
11

What is the slope of the line that passes through the points (5, 2) and (3,-1)?

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
3 0
Slope = -4/5

to calculate the slope m use the gradient form

m = y2 -y1
————
x2 - x1


let (x1, y1) = (3,1) and (x2, y2) = (-2, 5)


m = 5 - 1 4
———- = ——-
-2 - 3 -5


= - 4/5
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4 0
2 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
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let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

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\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

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2 years ago
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Read 2 more answers
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Answer:

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6 0
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