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yKpoI14uk [10]
2 years ago
9

PLEASE HELP I NEED TO FINISH THIS TODAY PLEASE BE RIGHT I NEED TO GET TO 70 AND I AM IN 54

Mathematics
1 answer:
zheka24 [161]2 years ago
6 0

Answer:

  • M"(-5, -7)
  • N"(-5, -3)
  • O"(0, -3)

Step-by-step explanation:

Each of the transformations can be written in terms of what they do to the coordinates:

  (x, y) ⇒ (-y, x) . . . . . . rotation 90° CCW

  (x, y) ⇒ (x -7, y-8) . . . . translation 7 left and 8 down

__

Together, these transformations result in the composite transformation ...

  (x, y) ⇒ (-y -7, x -8)

The end values of the original points are then ...

  M(1, -2) ⇒ M"(-(-2) -7, 1 -8) = M"(-5, -7)

  N(5, -2) ⇒ N"(-(-2) -7, 5 -8) = N"(-5, -3)

  O(5, -7) ⇒ O"(-(-7)-7, 5 -8) = O"(0, -3)

_____

<em>Additional comment</em>

You can get an idea of what the 90° rotation looks like by printing the figure and turning it 1/4 turn counterclockwise. The points will have the same relative locations with respect to the axes. Effectively, you are relabeling the x-axis to y, and the -y axis to x. (That is what the 90° CCW transformation formula is telling you.)

Alternatively, you can turn your head sideways when you look at the computer screen.

In the attachment, the black arrow represents the translation vector, 7 left and 8 down.

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I believe it is -332.
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To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you

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4.Construct KL¯¯¯¯¯ , the perpendicular bisector of ​ HJ¯¯¯¯¯ ​, intersecting​ ​ HJ¯¯¯¯¯ ​ ​​at point M.

5.Construct a circle with point M as the center with radius MJ .

6.Label the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point K, point N, and the point of intersection of circle M and ​ KL¯¯¯¯¯ ​  closest to point L, point O.

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3 0
3 years ago
If maria paid her supplier $8.50/doz for roses and sold them for $19.95,what was the percent markup?
Shkiper50 [21]

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Step-by-step explanation:


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Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

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2 years ago
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