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yKpoI14uk [10]
2 years ago
9

PLEASE HELP I NEED TO FINISH THIS TODAY PLEASE BE RIGHT I NEED TO GET TO 70 AND I AM IN 54

Mathematics
1 answer:
zheka24 [161]2 years ago
6 0

Answer:

  • M"(-5, -7)
  • N"(-5, -3)
  • O"(0, -3)

Step-by-step explanation:

Each of the transformations can be written in terms of what they do to the coordinates:

  (x, y) ⇒ (-y, x) . . . . . . rotation 90° CCW

  (x, y) ⇒ (x -7, y-8) . . . . translation 7 left and 8 down

__

Together, these transformations result in the composite transformation ...

  (x, y) ⇒ (-y -7, x -8)

The end values of the original points are then ...

  M(1, -2) ⇒ M"(-(-2) -7, 1 -8) = M"(-5, -7)

  N(5, -2) ⇒ N"(-(-2) -7, 5 -8) = N"(-5, -3)

  O(5, -7) ⇒ O"(-(-7)-7, 5 -8) = O"(0, -3)

_____

<em>Additional comment</em>

You can get an idea of what the 90° rotation looks like by printing the figure and turning it 1/4 turn counterclockwise. The points will have the same relative locations with respect to the axes. Effectively, you are relabeling the x-axis to y, and the -y axis to x. (That is what the 90° CCW transformation formula is telling you.)

Alternatively, you can turn your head sideways when you look at the computer screen.

In the attachment, the black arrow represents the translation vector, 7 left and 8 down.

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What is the area of FGH
Dmitrij [34]
54 in^{2}

A right triangle is a shape that looks like half of a square. The height of the triangle is 12, and the base of the triangle is 9. To find the area, use the following formula: 

A = \frac{bh}{2}


= \frac{12x9}{2}


= \frac{108}{2}


= 54 in^{2}
8 0
3 years ago
I would really appreciate it if someone could answer these as i'm really stuc and its due for tomorrow.
k0ka [10]
1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10

2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50

3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112

3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000

7 0
3 years ago
The cost of fencing a Square Garden is 400 at the rate of 1 per metre find its length​
grin007 [14]

Here Is The Answer:

Perimeter of garden = 400 m

side of square = 400 / 4

                       = 100 m

Area of garden => 100 m x 100 m

                        => 10000 m^2

Hope It Helps You!!!  

Have A Nice Day!!!  ^_^

8 0
3 years ago
The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
2 years ago
Equations must have combining like terms answer must be x=12
TEA [102]

Answer:

suppose

2x-x=12

x=12this is imagery answee

7 0
3 years ago
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