(HoG)(x) = (2x)2 + 4 simply because HoG(x) is actually H(G(x)). So where ever there was an x in H(x) we substitute our value of G(x). Now the only thing left is to put in the 1. so out answer is (2(1))2 + 4 = 8Only in the 6th grade ; )
First and third, second can still be simplified.
Answer:
The distance between the two given complex numbers = 9
Step-by-step explanation:
<u><em>Explanation</em></u>:-
<u><em>Step(i):</em></u>-
Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i
Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane
⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and
B = Z₂ = x₂+ i y₂ = 10 -9 i
Let (x₁ , y₁) = ( 9, -9)
(x₂, y₂) = (10, -9)
<u>Step(ii)</u>:-
<em>The distance between the two points are </em>
A B = 
A B = 
AB = 
<em> AB = √81 = 9</em>
<u><em>Conclusion:-</em></u>
The distance between the two given complex numbers = 9
<u><em></em></u>
Answer:
see explanation
Step-by-step explanation:
substitute the values of x in the table into g(x)
Using the rule of exponents
= 
g(- 2) =
=
= 
g(- 1) =
= 
g(0) =
= 1
g(1) =
= 4
g(2) = 4² = 16
Combinations = n! / (n - r)! r!

In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements