Question

Find the greatest possible number of consecutive zeros at the end of the product of three positive integers if the sum of these three integers equals 939.

Answer 1

Answer:

I think its 5 consecutive zeros.

Step-by-step explanation:

This would be a guess but I think you would need two numbers in the hundreds that also have 2 parts of which have a product of a number ending in 0, like 4 and 5.

So my guess would be

400 * 500 * 39

= 7800000