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harina [27]
2 years ago
6

Help its for calculus

Mathematics
2 answers:
amm18122 years ago
8 0

Answer:

the first one

Step-by-step explanation:

kirill [66]2 years ago
7 0

Answer:

its 1/sqrt{5}+2

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Helpppppppppppppppppp
irina [24]

Option D:

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Solution:

Given expression is \left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right).

<u>To find the product of the expression:</u>

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)

Multiply each term of the first term with each term of the 2nd term.

           =y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)

Using the exponent rule: a^m \cdot a^n = a^{m+n}

           =\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)

           =8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7

Arrange the terms with same power.

           =8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7

           =8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Hence option D is the correct answer.

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

6 0
3 years ago
Find the sum <br> (-8z+4)+(8z-7)
padilas [110]

Answer:

-3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
1 year ago
How do you write 5,392,029,004 in expanded form
Neko [114]
5,000,000,000 + 300,000,000 + 90,000,000 + 2,000,000 + 20,000 + 9,000 + 4
6 0
3 years ago
Frank's painting is on a large triangular canvas with side lengths 4 meters,
Mazyrski [523]

Answer:

3213 cm

Step-by-step explanation:

First draw the frame around the triangle. The circular edges added together give you 360 degrees. Use pi*r^2 to get 4pi which is around 12.56. 100cm=m. 2*500+2*400*2*700=3200.

3200+ 13 = 3213

3 0
3 years ago
Read 2 more answers
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