Answer:
the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910
Step-by-step explanation:
Given information:
mean, x = 5
standard deviation, σ = 0.9
number of sample, n = 16
now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.
P(x>4.73) = P (z > (4.73 - x) / (σ )
= P (z > (4.73 - 4) / (0.9 )
= P (z > 0.203)
= 0.5910