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zhannawk [14.2K]
1 year ago
11

The populations of two cities after t years can be modeled by -150t+50,000 and 50t+75,000 . What is the difference in the popula

tions of the cities when t=4 ?
Mathematics
2 answers:
Alex1 year ago
4 0
50t+34 t=4 is accelerating
creativ13 [48]1 year ago
3 0

Answer:

The difference in the populations of the cities when t=4 is 25,800.

Step-by-step explanation:

Given equations each of the city:

-150t+50,000

and

50t+75,000

To find the difference between the population when t=4, we first have to solve both equation when t=4.

For both equations, substitute 4 into t:

-150(4) + 50,000 = 49,400

50(4) + 75,000 = 75,200

Now subtract 49,400 from 75,200 and you get 25,800.

The difference in the populations of the cities when t=4 is 25,800.

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Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the slope of this graph; we are provided with two points:

\star~\mathrm{(6,0)}

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\triangle~\fbox{\bf{KEY:}}

  • What we need in order to find the slope are two points and the slope formula.

Here's the formula:

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Where

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Substitute the values:

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