Polly and Percy were sharing a bag of

Jose goes to the bodega. He

AysviL [449]

Answer:

1 bag of chips cost $1.25

Step-by-step explanation:

total money spent minus cost of soda = price of 2 bags of chips

$4.00- $1.50 = $2.50

2 bags of chips divided by 2 = price for one bag

$2.50 / 2 = $1.25

3 0

2 years ago

Find the area: someone help me

Anna35 [415]

The answer is 56m^2.
The formula for finding area of a triangle is A=b•h/2.
So the base is 16m and the height is 7m. 16m•7m=112m^2
Now divide 112m^2 by 2.
112m^2/2=56m^2

3 0

3 years ago

Is -6.06 a natural number

Rus_ich [418]

Answer:

Natural numbers are all positive numbers like 1, 2, 3, 4, and so on. They are the numbers you usually count and they continue till infinity. Whereas, the whole numbers are all natural numbers including 0, for example, 0, 1, 2, 3, 4, and so on. Integers include all whole numbers and their negative counterpart.

Step-by-step explanation:

3 0

2 years ago

QuizBIGPOINT

lianna [129]

The number of permutations of the problem is

This = 24
Outfit = 360

<h2>Combination</h2>

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Combinations are the number of ways to choose members from a certain number, namely from members of a set, combinations can also be interpreted as many ways to make subsets, namely with a certain number of members, namely from members of a set, if a set has n members then the selection of r members, and the combination of n is where r is less than n.

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<h3>The Formula : </h3>

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<h2>Permutation</h2>

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Permutations are a way to determine the number of arrangements that occur by paying attention to the order. So in permutations, position/order is very important, namely AB is considered different from BA (AB ≠ BA). Permutation formula

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<h3>The Formula :</h3>

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$\frac {n!}{k!}$ (With Double Elements)

n! (Without Double Elements)

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<h2>Factorial</h2>

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The factorial of a natural number is the successive multiplication of a natural number that begins with the number one and arrives at the natural number, the factorial is used in calculating combinations, probabilities, and permutations.

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<h3>For example</h3>

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》2! = 1 × 2
》3! = 1 x 2 x 3
》4! = 1 x 2 x 3 x 4
》5! = 1 x 2 x 3 x 4 x 5
》6! = 1 × 2 × 3 × 4 × 5 × 6
》7! = 1 × 2 × 3 × 4 × 5 × 6 × 7
》8! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8
》9! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9
》10! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10

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The following is an example of a factorial that does not involve mixed arithmetic operations, so if you want to add it up we just need to calculate it like a normal number, a factorial number that only multiplies the difference between a factorial number that is added up by addition, subtraction, multiplication, division, for example see below.

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6! x2! - 3! : 4!

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The example above is a mixed arithmetic operation that contains multiplication, subtraction, and division. Remember that in mixed arithmetic operations, multiplication/division must be completed before addition/subtraction.

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<h3>The Formula : </h3>

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n! (Combined Multiplication)

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<h2>Place Filling Rules</h2>

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The Place Fill Rule is a method or method that can be used to determine the number of ways an object occupies its place. The filling slots rule is a method of calculating how many possible ways there are in an experiment or event. If a first event can be done in m different ways and the second event can be done in a different way and so on until the last event in k.

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<h3>The formula</h3>

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n1 × n2 × n3 × ... × nr

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<h2><u>Question</u></h2>

Find the number of permutations of letters of the word

- this

- outfit

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<h2><u>Answer</u></h2>

"Number One"

=》This = Four Letters ( 4! )

P = 4!

P = 1 × 2 × 3 × 4

P = 2 × 3 × 4

P = 6 × 4

P = 24

==========

"Number Two"

=》Outfit = Six Letters ( 6! )

=》Outfit = Two Letters The Same ( "T" ) = 2!

P = $\frac {1×2×3×4×5×6}{2×1}$

P = $\frac {2×3×4×5×6}{2}$

P = $\frac {6×4×5×6}{2}$

P = $\frac {24×5×6}{2}$

P = $\frac {120×6}{2}$

P = $\frac {720}{2}$

P = 360

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<h2><u>Conclusion</u></h2>

So, the number of permutations of the problem is

This = 24
Outfit = 360

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<h2>Learn More</h2>

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<h2>Answer Detail</h2>

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➽ Subject: Mathematics
➽ Class : 12
➽ Chapter : 7 - The Rule of Counting:
➽ Maple Code
➽ Categorization code : 12.2.7
➽ Keywords : This, Outfit

5 0

3 years ago

Is 11/128 equal to a terminating decimal or a repeating decimal ? Explain how you know

Ostrovityanka [42]

We need to determine whether $\frac{11}{128}$ is a terminating decimal or a repeating decimal.

Let's solve this question using the long division method

First, let's identify the divisor and dividend. The number to be divided is 11 hence this is the dividend, and it needs to be divided by 128 which is the divisor

Next, since the divisor (128) is greater than the dividend (11) it can not divide 11. Hence, we will introduce a decimal point in quotient, and append a 0 next to 11 and divide 110 by 128. Again, 128 is greater than 110 so we will introduce a 0 in the quotient, and append another 0 next to 110, and will divide 1100 by 128. We will see what multiple of 128 is less than or equal to 1100. That multiple is 8. So we write 8 in the quotient and multiply 128 with 8 and subtract the product (128*8 = 1024) from 1100. The remainder that we get is 76.

Next, we append a 0 to the remainder and divide 760 by 128. Now, we see what multiple of 128 is less than or equal to 760. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 760. Now, the remainder is 120.

Next, we append a 0 to the remainder and divide 1200 by 128. Now, we see what multiple of 128 is less than or equal to 1200. That multiple is 9. So we write 9 next to the quotient and multiply 128 with 9 and subtract the product (1152) from 1200. Now, the remainder is 48.

Next, we append a 0 to the remainder and divide 480 by 128. Now, we see what multiple of 128 is less than or equal to 480. That multiple is 3. So we write 3 next to the quotient and multiply 128 with 3 and subtract the product (384) from 480. Now, the remainder is 96.

Next, we append a 0 to the remainder and divide 960 by 128. Now, we see what multiple of 128 is less than or equal to 960. That multiple is 7. So we write 7 next to the quotient and multiply 128 with 7 and subtract the product (896) from 960. Now, the remainder is 64.

Next, we append a 0 to the remainder and divide 640 by 128. Now, we see what multiple of 128 is less than or equal to 640. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 640. Now, the remainder is 0.

Hence, we have solved the entire problem

Last, we look at the quotient i.e. 0.0859375, which is the solution to the problem. We see that the quotient has a definite number of digits in it, and terminates at 5. Hence, this is a terminating decimal.

A repeating decimal is one in which a particular pattern after the decimal point keeps re-occuring, which is not the case here. Hence, $\frac{11}{128}$ is a terminating decimal.

Please refer to the attached image for visualization

3 0

3 years ago

Read 2 more answers