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scoundrel [369]
2 years ago
10

Find the midpoint of BF B(0,-14) F(4,6)

Mathematics
1 answer:
saveliy_v [14]2 years ago
7 0

Answer:

Step-by-step explanation:

B(0, -14) ⇒ x₁ = 0 & y₁ = -14

F(4,6) ⇒  x₂ = 4 & y₂ = 6

Midpoint = \left(\dfrac{x_{1}+x_{2}}{2}, \dfrac{y_{1}+y_{2}}{2} \right)

                =\left(\dfrac{0+4}{2},\dfrac{-14 + 6}{2}\right)\\\\\\= \left(\dfrac{4}{2}, \dfrac{-8}{2} \right)\\\\\\=\left(2, -4 \right)

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This can be simplified as :

= 3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})

We know that: \sqrt[3]{27}  = 3

Similarly we also can simplify: \sqrt[3]{b^6}  = b^2

So our expression will look like this:

= 3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})

= 9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})

=\sqrt[3]{2a}*(9b^2 + 3b^2)

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12b^2(\sqrt[3]{2a})

So the Answer is Option B


6 0
3 years ago
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Step-By-Step Explanation:

<u>Mean</u>

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