All categories

2 years ago

Consider this expression. What expression is equivalent to the given expression?

Mathematics

1 answer:

Lana71 [14]2 years ago

8 0

Answer:

brainliest?? :))

Step-by-step explanation:

You might be interested in

There are 135 people in a sport centre.

oksano4ka [1.4K]

Answer:

$\dfrac{1}{9}$

Step-by-step explanation:

4 people use all three facilities, then

16 - 4 = 12 people use the gym and the track and do not use the pool;
9 - 4 = 5 people use the pool and the track and do not use the gym;
19 - 4 = 15 people use the gym and the pool and do not use the track.

At least two facilities use 4 + 12 + 5 + 15 = 36 people, 4 of them use all three facilities. Thus, the probability that a randomly selected person which uses at least two facilities, uses all the facilities is

$\dfrac{4}{36}=\dfrac{1}{9}$

5 0

2 years ago

I came up the answer as 57. I will attach my note, can you check?

ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

$\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}$

so, we need a function that relates, angle, adjancent side and opposite side

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

replace

$\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}$

Step 2

BED

again, we have a rigth triangle,then let

$\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}$

so, we need a function that relates; angle, hypotenuse and adjacent side

$\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}$

replace.

$\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}$

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

$\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}$

so, the answer is 19

I hop

4 0

5 months ago

14. The sum of two integers is – 1.d

Alexxandr [17]

Answer:

a)The integers could be : -3 and 2

-4 and 3

-5 and 4

-9 and 10

--------------

b) the integers could be any pair -(x+1) and x with x a natural number

Step-by-step explanation:

3 0

2 years ago

A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.

Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be $4w+3l$ .