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2 years ago

Mark the sum as either positive or negative

Mathematics

2 answers:

tester [92]2 years ago

6 0

Answer:

1: Positive

2: Negative

3: Negative

4: Negative

Step-by-step explanation:

Positive plus Negative equals negative.

Positive plus positive or negative plus negative equals positive.

Hope this helps.

kicyunya [14]2 years ago

3 0

Step-by-step explanation:

-8+(-9) = -17 <--- Negative If they are both negative, then you do the simple math part and then add the negative sign

7+(-3) = 4 <---- Positive If there are only one negative, then you get rid of the '+' and then the equation turns into 7-3. You would do the simple math.

5+(-12) = -7 <----- Negative. Here, there is only one negative sign but the negative number is greater than the positive number. So, you would do the math 5-12 and use the negative sign.

-12+5 = -7 <----- Negative Look at the one above this.

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What theorem can be used to prove that the two triangles are congruent?

choli [55]

The answer is D)
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3 years ago

Please EXPLAIN how to get this answer so I can do it with other problems. A straight answer would be great, but I have to do abo

OLEGan [10]

Answer:

PQ = 3.58, and RQ = 10.4

Step-by-step explanation:

We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.

Hypotenuse = 11,

Opposite side is PQ

Adjacent side is RQ

x = 19

Sin x = (opposite side)/(hypotenuse)

Cos x = (adjacent side)/(hypotenuse)

For PQ, this is the side opposite to the angle, so use sin,

Sin 19 = x/11

11(Sin 19) = x

3.58 = x (rounded to the nearest hundredth)

For RQ, this is the side adjacent to the angle, so use cos,

Cos 19 = x/11

11(Cos 19) = x

10.4 = x (rounded to the nearest hundredth)

6 0

3 years ago

How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit

Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have ${13 \choose 2} = 78$ possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.