936 <span>39 </span>= 24
24 = 240 to the nearest tenth
24 = 24 to the nearest hundredth
24 = 24 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Answer:
B
Step-by-step explanation:
Not counting human error he should get exactly eight questions right using scicence, but since it is random there is margin of error that may disfigure the outcome.
Answer:
B. You have to distribute properties. So you distribute the exponent 5 to both the 6 & the 9
Answer:
0.05
Step-by-step explanation:
There are five letters to choose from. Since there is no repetition, you can choose one of 5 for the first letter, one of four for the second letter, etc. The total number of five-letter codes is
5 * 4 * 3 * 2 * 1 = 120
Now we need to find out the number of codes that start with M and end with E.
The first position is occupied by M. There is one single letter that can be placed there. The last position is occupied by E. There is a single letter that goes there. There are 3 letters left.
1 * 3 * 2 * 1 * 1 = 6
There are 6 codes that start with M and end with E
p(code that starts with M and ends with E) = 6/120 = 0.05
Answer:
The correct answer is 1
Step-by-step explanation:
The composite function g(f(x)) will be given by;
(1+x)^2 -(1+x)
Substituting x with zero yields g(f(0)) =0.
On the other hand, the composite function f(g(t)) will be given by;
1+t^2-t
Substituting t with zero yields f(g(0)) =1
Finally, g(f(0)) + f(g(0)) =0+1 = 1.
