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Gnom [1K]
2 years ago
13

During science class, Jack, Jeff, and Jill measure the length of their bean sprouts. Jeff’s sprout is 0.9 times the length of Ja

ck’s, and Jill’s is 1.08 times the length of Jack’s. Whose bean sprout is the longest?Why?
Mathematics
1 answer:
yKpoI14uk [10]2 years ago
8 0

Answer:

Jill's is the longest.

if jeffs is 0.9 times the length of jacks, his is lesser than jacks. e.g. 2×0.9=1.8. Jeff's will always be shorter. since we know Jacks is over 1, Jill's will always be taller because 2×1.08=2.16 or Jill's length.

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-\frac{9}{2}y=\frac{27}{2}
⇒-9y=27
⇒y=-3
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4 years ago
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When both parties discuss the terms of a contract, they are ____
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Hmm the answer should be D I just had that problem not to long ago on my worksheet :)
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a trapezoid has one base of 10 inches,an altitude of 6 inches and an area of 51 square inches, find the length of the other base
Inessa [10]

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ ---------\\ a=10\\ h=6\\ A=51 \end{cases}\implies 51=\cfrac{6(10+b)}{2} \\\\\\ 51=3(10+b)\implies \cfrac{51}{3}=10+b\implies 17=10+b\implies 7=b

5 0
3 years ago
If 95% and 98% confidence intervals were calculated from the same sample data in order to estimate the true cost of an appliance
damaskus [11]

Answer:

D) The z-statistics would be different.

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

  • M is the sample mean
  • ME is the margin of error from the mean

An margin of error (ME) from the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding z-statistic in the given confidence level
  • s is the population standard deviation
  • N is the sample size

If 95% and 98% confidence intervals were calculated from the same sample data, then M, s and N are same.

\frac{s}{\sqrt{N} } is called standard error. Since s and N are same the standard errors would also be same.

But, two tailed z-statistic for 95% confidence level is ≈1.96 where for 98% it is ≈2.33

8 0
3 years ago
the cost of three books and 2 pens is Rs.395 AND THE COST OF 2 BOOKS AND 5 PENS IS RS.355.FIND THE PRICES OF A BOOK AND A PEN
Alexandra [31]

Answer:

Assume as book to be x and pen to be y.

3x+2y=395 equation 1

2x+5y=355 equation 2

Make any variable either x or y to be equal.

3x*2+2y*2=395*2

2x*3+5y*3=355*3

Here, I am making x as same so I cross multiplied

6x+4y=790 equation 3

6x+15y=1065 equation 4

Put minus sign in any one of the equation 3 or equation 4 in order to cancel out x.

6x+4y=790

-6x-15y= -1065

0 - 11y= - 275

y= - 275/ - 11

y= 25

As we got y, we can put the value of y in equation 1 or equation 2.

3x+2y=395

3x+2*(25)=395

3x+50=395

3x=395-50

3x=345

x=345/3

x=115

As we assumed the book to x and pen to be y

price of book = Rs. 115

price of pen= Rs. 25

8 0
3 years ago
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