Answer:
Explanation:
Given data:
Rotating cylinder length = 9 mi
diameter of cylinder is 5.9 mi
we know that linear acceleration is given as
a = r ω^2
where ω is angular velocity
so
In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation
1 answer:
Answer:
the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers
Explanation:
The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:
15 - (1/200) L = 5 + (1/200) L
15 - 5 = (1/200) L + (1/200) L
10 = (2/200) L
(10*200)/2 = L
1000 = L
Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:
W = 15 - (1/200) L
W = 15 - (1/200) 1000
W = 10
Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers
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1) 0.77 m
2) 0.23 m
Explanation:
1)
Here we want to find the time elapsed for crouching in order to jump and reach a height of 2.0 m above the floor, starting from 1.0 m above the floor.
First of all, we start by calculating the speed required to jump up to a height of 2.0 m. Since the total energy is conserved, the initial kinetic energy is converted into gravitational potential energy, so:
where
m is the mass of the man
v is the speed after jumping
is the acceleration due to gravity
h = 2.0 - 1.0 = 1.0 m is the change in height
Solving for v,
In the acceleration phase, we know that the initial velocity is
And the force exerted on the floor is 2.3 times the gravitational force, so
This means the net force on you is
because we have to consider the force of gravity acting downward.
So the acceleration of the man is
Now we can use the following suvat equation to find the displacement in the acceleration phase, which is how low the man has to crouch in order to jump:
where s is the quantity we want to find. Solving for s,
2)
At the beginning, we are told that the height of the center of mass above the floor is
h = 1.0 m
During the acceleration phase and the crouch, the height of the center of mass of the body decreases by
This means that the lowest point reached by the center of mass above the floor during the crouch is
This value seems unpractical, since it is not really easy to crouch until having the center of mass 0.23 m above the ground.
Answer:
The magnitude of the force is 0.7255kN
Explanation:
The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:
(force of floor F) = (mass of person m) x [ (grav. acceleration g) - (elevator acceleration a) ]
in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:
We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:
So