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ratelena [41]
3 years ago
12

In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation

W = 5 + (1/200) L, where W is the wage rate and L is the quantity of labor. In this economy, the equilibrium wage rate is _____ and the equilibrium quantity of labor is _____ workers.
Physics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

the equilibrium wage rate is 10  and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

W_{Demand} = W_{Supply}

15 - (1/200) L = 5 + (1/200) L

15 - 5 =  (1/200) L +  (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

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The unit of charge is the Coulomb (C), and the unit of electric potential is the Volt (V), which is equal to a Joule per Coulomb (J/C).

Explanation:

4 0
3 years ago
2. An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in
a_sh-v [17]

Answer:

  t = 0.319 s

Explanation:

With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by

             v = √T/λ

Linear density is

           λ = m / L

           λ = 4/20

           λ = 0.2 kg / m

The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg

           T = W = mg

           T = 80 9.8

           T = 784 N

The pulse rate is

          v = √(784 / 0.2)

          v = 62.6 m / s

The time it takes to reach the hook can be searched with kinematics

          v = x / t

          t = x / v

          t = 20 / 62.6

          t = 0.319 s

7 0
3 years ago
Considering how the parts of a system work together and affect one another, other systems, and the environment is called _______
-BARSIC- [3]

Answer:

Hi

before I answer a question I think very deeply and try my best, hope it helps...

As you know there are many different types of systems. For example, The solar system, galaxies, quantum systems, atoms, molecules, orchestras, nervous system, etc, things you may not have even considered a system. To get to the basis of a system we must first understand what a system is then we will show some examples. A system is a group of Parts (parts could mean anything even dark energy and dark matter) that work together to accomplish something. For example, your body has many many trillions of cells that all try to accomplish the functions of humans which include thinking, moving, breathing, circulation, etc. Cells in turn are a system that have counterparts called organelles that accomplish harvesting energy, making new proteins, getting rid of waste, and so on. These are some systems which we highly dependent upon.

Well i hope it helped

Spiky Bob your answerer

8 0
2 years ago
Which is heavier, humid air or dry air ?
zvonat [6]

Answer:

dry air is way heaver

Explanation:

5 0
3 years ago
Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
3 years ago
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