2 years ago

!!please, please help me!!

Mathematics

1 answer:

grigory [225]2 years ago

6 0

Answer:

Length: 12

Width: 2 $\sqrt{10\\}$

Area: 24 $\sqrt{10\\}$

Step-by-step explanation:

We first find the points of C and D to find the length.

C: (-4,-5)

D: (2,-3)

The distance is 2 $\sqrt{10\\$ .

Now for the height.

A: (2,9)

D: (2,-3)

The distance is 12.

Area: 2 $\sqrt{10\\$ ×12 = 24 $\sqrt{10\\}$

You might be interested in

Box 1 contains 1000 lightbulbs of which 10% are defective. box 2 contains 2000 lightbulbs of which 5% are defective. (a) suppose

madreJ [45]

hhhhhhhhhhhhhhhhhhhhhhhhh

6 0

3 years ago

7. Please solve by substitution: y = 3x + 17 y = 2x + 23

CaHeK987 [17]

3x+17=2x+23

5x=40

40/5=8

x=8

7 0

3 years ago

Find f^-1(x) for f(x) = 1/x^3

kow [346]

Answer: $f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}$

Step-by-step explanation:

$y = \frac{1}{x^{3}}$

Inverse is when you swap the x's and y's and then solve for "y":

$x = \frac{1}{y^{3}}$

$y^{3} = \frac{1}{x}$

$y = \frac{1}{\sqrt[3]{x}}$

$y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}$

$y = \frac{\sqrt[3]{x^{2}}}{x}$

4 0

3 years ago

Round your answer to the nearest hundredth. A flower garden is 11.25 meters long. Mr. Owens wants to make a border along one si

vaieri [72.5K]

To find the answer just divide the length of a flower garden by the length of a brick:

11.25 / 0.25 = 45 (that's how many bricks are needed to be put).

There's nothing to round, but you can write it as a decimal to the hundredth place as 45.00.

8 0

2 years ago

jing spent 1/3 of her money on a pack of pens,1/2 of her money on a pack of markers, and 1/8 of her money on a pack of pencils w

Nataly_w [17]

1 - (1/3) = (2/3) Increase the denominator for LCM... (4/6) - (3/6) = (1/6) Increase again for LCM... (4/24) - (3/24) = (1/24 of her money left.)

Let me know if you need clarification :)

4 0

3 years ago