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2 years ago

Help me add 2/8 +5/8! I'm not too smart....

Mathematics

2 answers:

nignag [31]2 years ago

7 0

Answer:

7/8

Step-by-step explanation:

the answer to this is 7/8

Dafna11 [192]2 years ago

3 0

Answer:

the answer is 7/8

Step-by-step explanation:

because both are 8ths, they can be added together. please pay attention to your classes.

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The question is an illustration of permutation and combinations.

The number of ways she can choose 4 out of the 7 paintings is 35
The number of ways she can arrange 4 out of the 7 paintings is 840

The given parameters are:

$\mathbf{n = 7}$

$\mathbf{r = 4}$

<u>(a) Choose 4 of 7 paintings</u>

Choosing 4 of 7 paintings implies combination.

So, we have:

$\mathbf{^nC_r = \frac{n!}{(n - r)!r!}}$

Substitute values for n and r

$\mathbf{^7C_4 = \frac{7!}{(7 - 4)!4!}}$

$\mathbf{^7C_4 = \frac{7!}{3!4!}}$

Expand

$\mathbf{^7C_4 = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4 !}}$

$\mathbf{^7C_4 = 35}$

Hence, the number of ways she can choose 4 out of the 7 paintings is 35

<u>(b) Arrange 4 of 7 paintings</u>

Arranging 4 of 7 paintings implies permutation.

So, we have:

$\mathbf{^nP_r = \frac{n!}{(n - r)!}}$

Substitute values for n and r

$\mathbf{^7P_4 = \frac{7!}{(7 - 4)!}}$

$\mathbf{^7P_4 = \frac{7!}{3!}}$

Expand

$\mathbf{^7P_4 = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}}$

$\mathbf{^7P_4 = 840}$

Hence, the number of ways she can arrange 4 out of the 7 paintings is 840

Read more about permutation and combinations at:

brainly.com/question/15301090

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