Question

The area of parallelogram is 104 square units and base length is 13. What is the height of the parallelogram?

Answer 1

Answer :

• 8 units

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Step-by-step explanation :

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Here,

• Area of the parallelogram is 104 sq. units

• Base length of the parallelogram is 13 units.

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We know that,

${\longrightarrow \qquad{ \mathfrak{ \pmb{Base \times Height = Area_{(Parallelogram)}}}}}$

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Now, Substituting the values in the formula :

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${\longrightarrow \qquad{ \sf{ {13 \times Height = 104}}}}$

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${\longrightarrow \qquad{ \sf{ {Height = \dfrac{104}{13} }}}}$

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${\longrightarrow \qquad{ \pmb { \frak{Height \: \: {= 8}}}}}$

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Therefore,

• The Height of the parallelogram is 8 units.

Answer 2

Question :-

• The Area of Parallelogram is 104 units² . Its Base is 13 units . What is the Height of the Parallelogram ?

Answer :-

• Height of Parallelogram is 8 units .

Explanation :-

As per the provided information in the given question, we have been given that the Area of Parallelogram is 104 units² . Its Base is given as 13 units . And, we have been asked to calculate the Height of the Parallelogram .

For calculating the Height , we will use the Formula :-

$\bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Parallelogram} \: = \: Base \: \times \: Height \: }}$

Therefore , by Substituting the given values in the above Formula :-

$\dag \: \: \: \sf { Area \: _{Parallelogram} \: = \: Base \: \times \: Height }$

$\longmapsto \: \: \: \sf { 104 \: = \: 13 \: \times \: Height }$

$\longmapsto \: \: \: \sf { \dfrac {104}{13} \: = \: Height}$

$\longmapsto \: \: \: \sf { 8 \: = \: Height}$

$\longmapsto \: \: \: \textbf {\textsf {Height \: = \: 8 }}$

Hence :-

• Height of Parallelogram = 8 units .

$\underline {\rule {204pt} {4pt}}$

Additional Information :-

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$