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Alona [7]
3 years ago
7

Please help ASAP. The graph of a quadratic function is shown. Which of the numbers below could be the discriminant of the corres

ponding quadratic equation? a) 10 b) -1 c) 0 d) none of the above

Mathematics
2 answers:
juin [17]3 years ago
8 0

Answer:

10  option a)

Step-by-step explanation:

The discriminant has to be a number greater than zero, since we clearly see two solutions (crossings of the x axis) of the curve. So, the only option larger than zero among the possible answers is 10 (option a)

yuradex [85]3 years ago
6 0

Answer:

a

Step-by-step explanation:

Since the graph intersects the x-axis at 2 points, it has 2 solutions which means that the discriminant is greater than 0. The only option that satisfies this is 10.

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HURRY Please
NemiM [27]

B) The x-intercept indicates all tickets will be sold within 30 minutes

Step-by-step explanation:

From the equation of the function

f(x) = 200 -5x

The domain of f(x) is [0,40] for values of x that are true and the range is [0,200] for values of y from corresponding values of x

The constant 200, is the y-intercept which indicates that at the starting time of selling the tickets, 200 tickets were available

The slope, -5 indicates that the tickets were being sold at a rate of 5 tickets per minute. This shows that in 40 minutes,the 200 tickets will be sold out.

Learn More

To interpret linear functions:brainly.com/question/13599312

Keywords ;theater, ticket, inventory, movie, modeled, function, minutes, elapse, graph, domain, statement, false

#LearnwithBrainly

7 0
4 years ago
Read 2 more answers
Which expression is equivalent to square root 55x^7y6/11x^11y^8
Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
3 years ago
An electrician has 14/15 yard of wire. He used 5/7 of wire. How many yards of wire did the electrician use?
siniylev [52]
23/105 i think :) sorry if im wrong

5 0
3 years ago
Read 2 more answers
Write the expression as a single logarithm
vlada-n [284]

took the test. answer is logb(y^4x^3), or A.

4 0
4 years ago
The vertices of a square are A(–2, 4), B(4, 4), C(4, –2), and D(–2, –2). The diagonals of the square intersect at their midpoint
sertanlavr [38]
A(–2, 4), B(4, 4), C(4, –2), D(–2, –2)
-> select some diagonal: AC
midpoint is at A+(1/2)*AC

-> calculate vector AC:
AC=(4-(-2),-2-4)=(6,-6)
-> calculate half length of AC:
(1/2)*AC=(3,-3)

A+(1/2)*AC=
(-2,4)+(3,-3)=(1,1) which is the midpoint

so the first option is correct
4 0
3 years ago
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