Answer:
2
Step-by-step explanation:
Simplify the following:
(-(2 + 2/3))/(-(1 + 1/3))
(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):
(2 + 2/3)/(1 + 1/3)
Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:
(2 + 2/3)/(3/3 + 1/3)
3/3 + 1/3 = (3 + 1)/3:
(2 + 2/3)/((3 + 1)/3)
3 + 1 = 4:
(2 + 2/3)/(4/3)
Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:
((3×2)/3 + 2/3)/(4/3)
3×2 = 6:
(6/3 + 2/3)/(4/3)
6/3 + 2/3 = (6 + 2)/3:
((6 + 2)/3)/(4/3)
6 + 2 = 8:
(8/3)/(4/3)
Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:
(8×3)/(3×4)
(8×3)/(3×4) = 3/3×8/4 = 8/4:
8/4
The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:
Answer: 2
A: Commutative Property of Addition
Barney can save
$119.66
in interest over the course of a year if he transfers his balance to a credit
card with an APR of 19.1%, compounded monthly. The correct answer between all
the choices given is the first choice or letter A.
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
Answer:
omg im still dont no
Step-by-step explanation:
sorry