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mina [271]
3 years ago
13

Combine these radicals.

Mathematics
1 answer:
kherson [118]3 years ago
3 0
..? I don't see anything
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The cost of having a window fixed is $100 plus $20 per hour of labor. Using h for the number of hours of labor, write an express
kipiarov [429]

Answer:

Step-by-step explanation:

labor cost = 20 * h = 20h

Total cost = 100 + 20h

3 0
4 years ago
You’re given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side
erma4kov [3.2K]
To find the third side of a triangle (there are two answers you could get), you need to use the Pythagorean formula: a^2+b^2=c^2.  First answer, 3^2+5^2=c^2.  Solve for c.  c=5.83.  The second answer, 3^2+b^2=5^2.  Solve for b.  b=4.
4 0
3 years ago
Please help me with this question
sashaice [31]

Answer:

the answer is b hope it helps

Step-by-step explanation:

Let's simplify step-by-step.

3y2−9y+4r10

=3y2+−9y+4r10

Answer:

=4r10+3y2−9y

5 0
4 years ago
I need help with these questions
inysia [295]

Answer:

28. m<A=20°, m<B=70°

32. m<A=103°, m<B=77°

Step-by-step explanation:

complementary angle=a+b=90°

supplementary angle=a+b=180°

28. A+B=90°

      5x+17x+2=90°

      22x+2=90°

      22x=90-2

      22x=88

        22x/22=88/22

      x=88/22=<u>4</u>

m<A=5x=5*4=<u>20°</u>

m<B=17x+2=17*4+2=68+2=<u>70°</u>

         <u>Check</u>

A+B=90°

20+70=90°

<u>90°=90°</u>

32. A+B=180°

     x+11+x-15=180°

     2x-4=180°

     2x=180+4

     2x=184

     2x/2=184/2

     x=184/2

     x=<u>92</u>

m<A=x+11=92+11=<u>103°</u>

m<B=x-15=92-15=<u>77°</u>

     <u>Check</u>

A+B=180°

103+77=180°

<u>180°=180°</u>

6 0
3 years ago
1+Sin/Cos + Cos/1+Sin = 2Sec
Bond [772]

Step-by-step explanation:

Consider the left-hand side:

\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}

\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:= \dfrac{2}{\cos{\theta}} = 2\sec{\theta}

7 0
3 years ago
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