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slava [35]
2 years ago
9

Placing a down payment on a home is a common practice among homebuyers and, in many cases, is required by the lender for eligibi

lity reasons. As the Payans’ real estate agent suggested in part C, it’s also important to help keep the mortgage payment low and within the homebuyer’s monthly budget to avoid the risk of default. Write two to three sentences summarizing what might happen if the Payans were to default on their monthly mortgage payments.
Mathematics
1 answer:
Komok [63]2 years ago
6 0

Answer:

If the Payans were to default, their credit score could be lowered. The Payans could also lose their house. With both of those things on their record, it would make it harder for the Payans to qualify for another loan.

Hope this helps!

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Identify the slope and intercept of the following linear equation.
IrinaK [193]

Answer:

3/7 is the slope and -5 is the y intercept

Step-by-step explanation:

y=3/7x-5

The equation is written in slope intercept form

y = mx+b where m is the slope and b is the y intercept

3/7 is the slope and -5 is the y intercept

3 0
3 years ago
Read 2 more answers
Write 0.083333333333333 repeating as a fraction. (The 3 is repeating the 8 is not)
saul85 [17]
The answer is 83/1000 in it's simplest form.
4 0
3 years ago
A - Frequency
Marina CMI [18]

Answer:

Step-by-step explanation:

When we collect a large data we may find a single entry repeated.  In these cases we prepare frequency distribution with x = the item in one column and f = the no of times it repeats i.e. frequency in other column.

Similarly for class intervals also, we write as frequency to the right side of interval column which gives no of items which fall within the class.

This process ensures compact presenting of data.

Hence we have

a)The number of observations that fall in a class

answer:   Frequency

b) The relative frequency of a class multiplied by 100

answer:   Percentage.  Because when we express probability as a percentage we get total 100

c) The ratio of the frequency of a class to the total number of observations

answer:  Relative frequency

(Relative frequency also known as probability is frequency/total entries)

8 0
3 years ago
Read 2 more answers
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
A rental car company is running two specials. Customers can pay $40 to rent a compact car for the first day plus $6 for each add
Flura [38]

Answer: she wants to rent the car for 11 days.

Step-by-step explanation:

Let x represent the number of additional days that Pamela wants to rent the car for.

Customers can pay $40 to rent a compact car for the first day plus $6 for each additional day. This means that the total cost of using this special for x days would be

40 + 6(x - 1) = 40 + 6x - 6

= 34 + 6x

Also, they can rent the same car for $30 the first day and $7 for every additional day beyond that. This means that the total cost of using this special for x days would be

30 + 7(x - 1) = 30 + 7x - 7

= 23 + 7x

Since she found out that the two specials are equivalent for x days, then

34 + 6x = 23 + 7x

7x - 6x = 34 - 23

x = 11

4 0
4 years ago
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