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Serggg [28]
3 years ago
11

Solve for x in the following equation: x/a = y/b

Mathematics
1 answer:
nadya68 [22]3 years ago
6 0
<span>As you have two fractions, you can cross multiply them. This gives: x/a = y/b to ay = xb. Then divide both sides by b to isolate x: ay/b = x.</span>
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This figure is 14 of a circle.
Wittaler [7]

Answer:

The perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.

Step-by-step explanation:

Given : A quarter of a circle with radius labeled 2 in.

Quarter of circle means fourth part of a circle  (as shown in image by shaded part).

We have to find the perimeter of this shaded quarter of circle.

Perimeter is the sum of the dimension of the given figure.

Perimeter of circle is 2\pi r

Since, we are given Quarter circle so its perimeter \frac{2}{4} \pi r+r+r=\frac{1}{2} \pi r+r+r

Perimeter of given figure = \frac{1}{2} \pi r+r+r

Perimeter of given figure = \frac{1}{2}\cdot 3.14 \cdot 2+2+2=3.14+4=7.14

Thus, the perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.

6 0
3 years ago
Read 2 more answers
A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to buy the watch ? <br>​
Svetlanka [38]

Answer:

Rupees 891

Step-by-step explanation:

If you multiply 810 times 0.1 which is the decimal of 10%, you get 81 which you can add to 810 to get 891 which is the price the shopkeeper payed to buy the watch.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0
3 years ago
Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.        A. s ≤ 9   B. s ≤ 3   C. s ≤ 1/3   D. s ≤ 5/9  
Kitty [74]
The answer wil be B.
7 0
3 years ago
PLEASE HELP! Please I’m having a hard time with this I’ll be thankful
Arlecino [84]

Answer:

80 and 96

Step-by-step explanation:

80 and 96

7 0
3 years ago
Read 2 more answers
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
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