Just by looking at 14 it will be non linear since any equation that has an exponent will automatically be non linear and will not form a straight line. 13 would be linear as when you subtract x from both sides you’ll have a straight line meaning it’s linear. And 12 will be linear because the equation once into y=mx+b format it will be y=-2x/3+7/3 making a straight line if graphed correctly.
Answer:
what is this in? please let me kno2
Answer:
We know that:
If T = area of the triangle
and R = area of the rectangle:
I T - RI < 4.
Now, we know that:
T = 8*6/2 = 8*3 = 24
R = 4*(x - 4) = 4*x - 16
Then replacing those values, we can write:
I24 - (4*x - 16)I < 4
I40 - 4*xI < 4
Now let's solve it:
First we aim for the first value that is not a solutions, this is when:
I40 - 4*xI = 4
we can write this as:
40 - 4*x = +-4
The first extreme is:
40 - 4*x = +4
x = (40 - 4)/4 = 9
The other extreme is:
40 - 4*x = -4
x = (40 + 4)/4 = 11.
Then the set of solutions is: S = (9, 11)
F(-5) is 23-D
Line change is B
Answer:
The perimeter of the rectangle is 18 units.
Step-by-step explanation:
The image included below presents the location of the points on the Cartesian plane. From Geometry we get that the perimeter (
), dimensionless, of the rectangle is the sum of its four sides. That is to say:
(1)
Where 
, 
, 
and 
are the sides of the rectangle, dimensionless.
Each side value is found by means of the Pythagorean Theorem:
![AB = \sqrt{[2-(-1)]^{2}+(1-1)^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%5B2-%28-1%29%5D%5E%7B2%7D%2B%281-1%29%5E%7B2%7D%7D)
![BC = \sqrt{(2-2)^{2}+[(-5)-1]^{2}}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%282-2%29%5E%7B2%7D%2B%5B%28-5%29-1%5D%5E%7B2%7D%7D)
![DA = \sqrt{(-1-1)^{2}+[1-(-5)]^{2}}](https://tex.z-dn.net/?f=DA%20%3D%20%5Csqrt%7B%28-1-1%29%5E%7B2%7D%2B%5B1-%28-5%29%5D%5E%7B2%7D%7D)
And the perimeter of the rectangle is:
The perimeter of the rectangle is 18 units.
