All categories

3 years ago

In 2001, the world population 6.5 billion and was increasing at a rate of 1.2% each year.

Mathematics

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer:

8.0 billion

Step-by-step explanation:

1.2÷100=0.012

0.012×6.5=0.078

2017-2001=16

0.078×16=1.248

6.5+1.248=7.748

nearest tenth 8.0

You might be interested in

5-(8v+5)= -4(1 + 3v)

Lilit [14]

5-(8v+5) = -4(1+3v)
5-8v-5 = -4 - 12v
-8v = -4 - 12v
4v = -4
v = -1

8 0

3 years ago

Read 2 more answers

Peter paid $9.75 to go to the movies, which was $46.25 less than he paid to go to a concert. How much did he pay for the concert

Levart [38]

Answer:

He payed 56 dollars for the concert.

Step-by-step explanation:

46.25 + 9.75= 56

3 0

3 years ago

Height of a parallelogram is half it's base.if it's area is 200 sq cm.find it's height and base.

Scilla [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago

What does -2(-5x+9)-9x equal

Ann [662]

-2(-5x+9)-9x
-2(-5x)+-2(9)-9x
10x-18-9x
+9 +9
19x=-18
---- ----
19 19
x=-1.05

7 0

3 years ago