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Anon25 [30]
3 years ago
10

I need help plz:((((((((((

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

a) y=\frac{28}{75}(x-1900)+47.3

b) 86.5 years

Step-by-step explanation:

All values are rounded to 2 decimal places

a) We can find line by using y =mx+b

y=mx+b\\m=\frac{y^{2}-y^{1} }{x^{2}-x^{1}}\\m=\frac{69.7-47.3}{1960-1900} \\m=\frac{22.4}{60} \\m=\frac{28}{75}\\c=y-intercept\\y-intercept=47.3\\y=\frac{28}{75} (x-1900)+47.3

Therefore the line of best fit is y=\frac{28}{75}(x-1900)+47.3\\

b) We can do this by using the formula of the best fit line to estimate the life expectancy of someone born in 2005

y=\frac{28}{75}(x-1900)+47.3\\y=\frac{28}{75}(2005-1900)+47.3\\y=\frac{28}{75}\times105+47.3\\y=86.5

Therefore the estimated life expectancy of someone born in 2005 is 86.5 years

PS. Please give brainliest answer this was a lot of working out

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