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Anon25 [30]
3 years ago
10

I need help plz:((((((((((

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

a) y=\frac{28}{75}(x-1900)+47.3

b) 86.5 years

Step-by-step explanation:

All values are rounded to 2 decimal places

a) We can find line by using y =mx+b

y=mx+b\\m=\frac{y^{2}-y^{1} }{x^{2}-x^{1}}\\m=\frac{69.7-47.3}{1960-1900} \\m=\frac{22.4}{60} \\m=\frac{28}{75}\\c=y-intercept\\y-intercept=47.3\\y=\frac{28}{75} (x-1900)+47.3

Therefore the line of best fit is y=\frac{28}{75}(x-1900)+47.3\\

b) We can do this by using the formula of the best fit line to estimate the life expectancy of someone born in 2005

y=\frac{28}{75}(x-1900)+47.3\\y=\frac{28}{75}(2005-1900)+47.3\\y=\frac{28}{75}\times105+47.3\\y=86.5

Therefore the estimated life expectancy of someone born in 2005 is 86.5 years

PS. Please give brainliest answer this was a lot of working out

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65970
6.597 * 10^4
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3 years ago
The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of
Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

X \sim N(3.34,0.07^2)

Value let separated the top 3% is T and for bottom it would be B

P(X < T)= 0.97

Now converting, we get

P(Z < \frac{T-3.34}{0.07})= 0.97

Based on the normal standard tables, we get

P(Z < 1.881)= 0.97

Now compare these two above equations

\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

P(Z < \frac{B-3.34}{0.07})= 0.03

Based on the normal standard tables, we get

P(Z < -1.881)= 0.03

Now compare these two above equations

\frac{B-3.34}{0.07} = -1.881

= -1.881 \times 0.07 + 3.34 \\\\ = 3.21

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7 0
3 years ago
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

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\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

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7 0
3 years ago
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Answer:

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=0.015234

7 0
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