Find the domain over which the function y = x + 6x is monotonic increasing.

Mathematics

1 answer:

iragen [17]2 years ago

4 0

Answer:

x > -3

$\sf (-3, \infty)$

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing: always increasing.
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola. If the leading term is positive, the parabola opens upwards. The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation: $\sf y=ax^2+bx+c$

$\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}$

Given function:

$\sf y=x^2+6x$

Therefore, x-value of function's vertex:

$\sf \implies x= -\dfrac{6}{2}=-3$

<u>Final Solution</u>

The function is increasing when x > -3

$\sf (-3, \infty)$

You might be interested in

Can someone plssss answer this.

goblinko [34]

1: B
because a triangle angles all have to add up to 180

8 0

2 years ago

Please help i dont understand

Greeley [361]

Given:

A quadrilateral inscribed in a circle.

To find:

The value of x and y.

Solution:

If a quadrilateral inscribed in a circle, then it is known as cyclic quadrilateral and the opposite angles of a cyclic quadrilateral are supplementary angles, it means their sum is 180 degrees.

$5x^\circ+110^\circ=180^\circ$ [Supplementary angles]