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2 years ago

Given that

Mathematics

2 answers:

nadya68 [22]2 years ago

8 0

Answer:

25/3

Step-by-step explanation:

3x:10=5:2

proportions are basically ratios, and ratios are basically fractions, so we can cross multiply

3x*2=10*5

6x=50

x=50/6

x=25/3

Luba_88 [7]2 years ago

5 0

Step-by-step explanation:

please mark me as brainlest

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A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.

makvit [3.9K]

<h3>Answer: 7366.96 dollars</h3>

========================================================

Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

-------

Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

12000 = P(1.05)^(10)

12000 = P(1.62889462677744)

12000 = 1.62889462677744P

1.62889462677744P = 12000

P = 12000/1.62889462677744

P = 7366.95904248911

P = 7366.96

6 0

3 years ago

Identify as many solutions to the equation below as you can.<br> x + y = 12

harkovskaia [24]

Answer:

infinite

Step-by-step explanation:

because there is an infinite amount of numbers there is an infinite amount of solutions

5 0

2 years ago

Three times the sum of a number and two is equal to -9.

Svetllana [295]

Answer:

Step-by-step explanation:

use a equation calculator it really helps

8 0

3 years ago

Which set of ordered pairs represents y as a function of ?

ollegr [7]

B......................

8 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago