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Katen [24]
3 years ago
6

Helpp I’ll Mark you brainiest if your correct

Mathematics
1 answer:
patriot [66]3 years ago
6 0
The answer is 586.17 cm^2
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A rectangle is a special type of: I. Pentagon II. Circle III. Quadrilateral IV. Triangle
dimulka [17.4K]
The correct answer is the third choice, Quadrilateral.
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3 years ago
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Brenda has two pieces of string, one 28 feet long and the other 42 feet long. For an art project, she wants to cut them up to pr
NeTakaya

Answer:

7 feet

Step-by-step explanation:

Length of one piece of string = 28 feet.

Length of the second string = 42 feet.

Since the number of required pieces was not given but many are required, the greatest length can be determined by;

If the maximum length is 7 feet, then:

the number of pieces from 28 feet long string = \frac{28}{7}

                                                      = 4

Also,

the number of pieces from the 42 feet lone string = \frac{42}{7}

                                                    = 6

Total number of 7 feet strings that she can make = 4 + 6

                                                    = 10

Since many pieces are required, the greatest length she can make is 7 feet. If she increase the length to 14 feet, the number of pieces would be 5 which limit the required number.

3 0
3 years ago
755,082 round to nearest ten thousand
scZoUnD [109]
755,082 rounded to the nearest ten thousand is 760,000
6 0
3 years ago
write a systems of equation where one equation has a slope of 2 and goes through the point 0, 2 and the second equation is paral
AleksandrR [38]

Answer:

go up the hill and roll down then you willf igure it out

Step-by-step explanation:

5 0
3 years ago
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Un aljibe de 12.4 m de profundidad se encuentra totalmente lleno de agua. ¿Cual es la presión en el fundo debido únicamente al p
Kamila [148]

Answer:

a) p = 121644 Pa

b) p_{T} = 221644 Pa  

Step-by-step explanation:

a) La presión en el fondo debido únicamente al peso del agua se puede calcular usando la siguiente ecuación:

p = \rho gh

En donde:

ρ: es la densidad del agua = 1000 kg/m³

g: es la gravedad = 9.81 m/s²

h: es la profundidad = 12.4 m

p = \rho gh = 1000 kg/m^{3}*9.81 m/s^{2}*12.4 m = 121644 Pa

Entonces, la presión en el fondo debido al agua es 121644 Pa.

b) Para hallar la presión total en el fondo debemos ahora considerar la presión atmosférica:

p_{T} = p_{0} + \rho gh  

En donde p₀ es la presión atomsférica = 75 cmHg

p_{T} = 750 mmHg\frac{1 Pa}{0.0075 mmHg} + 121644 Pa = 221644 Pa

Por lo tanto, la presión total en el fondo es 221644 Pa.

Espero que te sea de utilidad!

4 0
3 years ago
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