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Katen [24]
2 years ago
6

Helpp I’ll Mark you brainiest if your correct

Mathematics
1 answer:
patriot [66]2 years ago
6 0
The answer is 586.17 cm^2
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Applying Rate of change
olga nikolaevna [1]
\bf \begin{array}{ccllll}
minutes(x)&Mbs\ left(y)\\
-----&-----\\
2&38.4\\
8&9.6
\end{array}\\\\
-----------------------------\\\\
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\impliedby \textit{rate of change}
\\\\\\
m=\cfrac{9.6-38.4}{8-2}\implies m=-\cfrac{24}{5}\iff m= -4.8

now, notice, the rate of change for downloading is negative, because, "y" is decreasing,  namely the Mbs to be downloaded, are less and less and less as the minutes go by, because the file is almost fully downloaded

so is -4.8

now... at 8minutes, there are 9.6Mbs to download
bear in mind that 9.6 is just 4.8 * 2
that simply means, another minute, another 4.8 Mbs, and another minute and another 4.8 Mbs and the file is done

so, the file downloaded really in 10minutes

now, we know the rate is -4.8 or -24/5,   let us nevermind the sign for now

since we know the file is downloading at 24Mbs in 5minutes, a rate of 24/5

how much is it for 10 minutes?   well 10 is really just 5 * 2

so if it downloads at a rate of 24Mbs per 5mins, in 10 minutes it downloaded 24*2 or 48Mbs
7 0
3 years ago
Calculate s_75 for the arithmetic sequence defined by {a_n}={67-2n}
nalin [4]

Answer:

we go to the same school

Step-by-step explanation:

kik me at my name

3 0
3 years ago
Theo drove 236 miles in 4 hours. Lex drove 195 miles in 3 hours. At those rates, could either man drive 116 miles in 2 hours? Sh
motikmotik

Answer:

No.

Step-by-step explanation:

236÷4=59

     &

195÷3=65

<em>To check if either of them drove 116 miles in 2 hours, I would multiply the sum of the division problems by 2(for 2 hours).</em>

59 x 2 = 118

      &

65 x 2 = 130

None of them equals 116, meaning neither of them drove 116 miles in 2 hours.

<u><em>Hope I helped you! Have a great day! :)</em></u>

6 0
3 years ago
Carly lives in Scottsdale, AZ and plans to go visit downtown Glendale, AZ. The map with a scale of 2 cm for every 4 km shows the
AleksandrR [38]
Comparing map distance to real distance we get 2cm/4km. That means 1cm = 2km.

So the map distance is half the real distance (well, technically not as one is in cm and the other in km but it’s enough to think this way) and a real distance of 10km must mean a map distance of half that (again ignoring the units) so we get 5cm.
5 0
3 years ago
Read 2 more answers
Which graph represents the solution set of the compound inequality -43x-1 and 2x+43 18?
r-ruslan [8.4K]

Answer:

Step-by-step explanation:

YOU CAN DO THIS :)

7 0
2 years ago
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