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BARSIC [14]
3 years ago
14

There are 2 red and 5 green balls in a bag. If you randomly choose balls one at a time , with replacement , What is the probabil

ity of choosing 2 green balls and then 1 red ball?
A. 2/21
B.20/147
C.50/343
D. 5/21
Mathematics
2 answers:
Nikolay [14]3 years ago
8 0

Option C

<u>ANSWER:  </u>

The probability of choosing 2 green balls and 1 red ball is \frac{50}{343}

<u>SOLUTION: </u>

Given, there are 2 red and 5 green balls in a bag.

So, there are 7 balls in the bag.

We need to find the probability of choosing 2 green balls and 1 red ball.

Probability of 2 green balls and 1 red ball = probability of 1st green ball \times probability of 2nd green ball x probability of 1 red ball.

Now, probability of 1st green ball = \frac{\text {number of green balls}}{\text {total number of balls}}

= \frac{5}{7}

because we are replacing after every pick.

Now, probability of red ball = \frac{\text {number of red balls}}{\text {total number of balls}}

=\frac{2}{7}

Probability of 2 green balls and 1 red ball = \frac{5}{7} \times \frac{5}{7} \times \frac{2}{7}

=\frac{5 \times 5 \times 2}{7 \times 7 \times 7}

=\frac{50}{343}

Hence, the probability of choosing 2 green balls and 1 red ball is \frac{50}{343}

Musya8 [376]3 years ago
4 0

Answer:

D is the answer

Step-by-step explanation:

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Answer:

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Let me know if this helps!

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HELP ASAP!! What’s the answer to this? (with steps)
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Step-by-step explanation:

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