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2 years ago

Complete this pattern and write a short sentence explaining the pattern.

Mathematics

1 answer:

alina1380 [7]2 years ago

4 0

Answer:

the pattern is to divide by 2

Step-by-step explanation:

so instead of 0 it would be 1

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Determite weather the ordered pair is a solution of the linear equation x=y+1/2;(-5,-2)

Minchanka [31]

Answer:

(y+1/2 ; y)

Step-by-step explanation:

hello : all ordered pair is a solution of the linear equation x=y+1/2;(-5,-2) is :

(y+1/2 ; y)

(-5 ; -2) is not solution because y = -2 but -2+1/2 = -3/2 no -5

7 0

2 years ago

One fifth of a number plus five times that number is equal to seven times the number less 18. find the number.

Schach [20]

OK. First we have to figure out names for all the numbers you mentioned.

The mysterious number . . . . . call it Q
One fifth of the number . . . . . 0.2 Q
Five times the number . . . . . . 5 Q
Seven times the number . . . . 7 Q

(One fifth plus five times the number) . . . 5.2 Q
(Seven times the number less 18) . . . . . . 7 Q - 18

You said that these last two things are equal,

so I can write . . . . . . . . . . . . . . . . . . 7 Q - 18 = 5.2 Q

Now, subtract 7Q from each side . . . -18 = -1.8 Q

Divide each side by -1.8 . . . . . . . . . . 10 = Q

6 0

2 years ago

Use the Normal model N(98,15) for the IQs of sample participants. What IQ represents the 17th percentile? Use the appropriate

maxonik [38]

Answer:

=NORM.INV(0.17,98,15)

Step-by-step explanation:

Consider X represents the IQs of sample participants.

Then X follows the Normal Distribution with mean 98 and standard deviation 15.

That is,

$X \sim N(98,15)$

The probability value is 17th percentile (that is 0.17)

To find the value of X using Excel, the<em> Inverse Normal Distribution </em>is used.

The Excel function =NORM.INV(0.22,105,17) is used to find the IQs of sample participants.

7 0

3 years ago

If x^3 + 1/x^3 = 110 then find x + 1/x

Svetlanka [38]

$Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)$

therefore

$x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}$

3 0

2 years ago

X^1/2 + 1 is it a poynomial? explain

Gennadij [26K]

Answer:

I think so!

Step-by-step explanation:

Because any Expression that has 1 or more terms is a polynomial

3 0

1 year ago