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Dima020 [189]
2 years ago
11

The first three terms of a sequence are given. Round to the nearest

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0

Answer:

I'm sorry I don't know

Step-by-step explanation:

hopefully someone solves this!

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UkoKoshka [18]
Yes, it is a function
4 0
3 years ago
Read 2 more answers
What is x to the power of 2 multiplied by negative 3x
melamori03 [73]

x^2*(-3x)=-3x^3. The power of x becomes 3 because you add the powers of x. (2+1=3)


3 0
3 years ago
if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect
iogann1982 [59]

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

E(x) = x*7.6x10^10 J

And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

4 0
3 years ago
What is BQD’s degree
AveGali [126]

Answer:i dont know

Step-by-step explanation:

5 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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