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Goryan [66]
3 years ago
5

What is the solution of the system defined by y= -x+5 and 5x + 2y = 14?

Mathematics
1 answer:
telo118 [61]3 years ago
5 0
          y = -x + 5
5x + 2y = 14

     5x + 2(-x + 5) = 14
5x + 2(-x) + 2(5) = 14
       5x - 2x + 10 = 14
              3x + 10 = 14
                    - 10  - 10
                      3x = 4
                       3     3
                        x = 1¹/₃
      y = -x + 5
      y = -1¹/₃ + 5
      y = 3²/₃
(x, y) = (-1¹/₂, 3²/₃)
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See sample space below

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The sample space refers to the set of all the possible outcomes.

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3 years ago
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Lynna [10]

Answer:

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3 years ago
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Consider the polynomial function.
svp [43]

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<h3>Rule of Descartes</h3>

This states that the number of real positive zeros of a polynomial are equal to or less than by an even number the number of sign changes of the coefficients of the polynomial, f(x). Also, the number of real negative zeros of a polynomial are equal to or less than by an even number the number of sign changes of the coefficients of the polynomial, f(-x).

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Since f(x) = x⁴ + 2x³ - 11x² - 5x - 6

The cofficients are +1, + 2, -11, -5, -6

There is no sign change from + 1 to + 2.

There is a sign change from + 2 to - 11.

There is no sign change from - 11 to - 5.

There is no sign change from -5 to - 6.

Since there is only one sign change, there is 1 positive zero.

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The cofficients are +1, - 2, -11, +5, -6

There is a sign change from + 1 to - 2.

There is no sign change from - 2 to - 11.

There is a sign change from - 11 to + 5.

There is a sign change from +5 to - 6.

Since there are 3 sign changes, we have 3 or 3 - 2 = 1 negative zeros.

So, the number of positive zeros is 1. The number of negative zeros is either 3 or 1.

Learn more about rule of descartes here:

brainly.com/question/11444977

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Answer:

The answer to the question is

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