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gogolik [260]
3 years ago
11

35. V112 + V63 How do I solve this please

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer: 175V

Step-by-step explanation:

V112+V63=112v+63V

Add them together because the terms are like terms. Therfore, 112V+63V=175V

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Irina18 [472]

Answer:

\bf C)\: -\cfrac{1}{32}

Step-by-step explanation:

\tt \cfrac{1}{2^{-2}x^{-3}y^5}

\tt x=2\\y=-4

~

Substitute ''x'' with '2' & 'y' with "-4":-

\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}

First let's solve \tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5

\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }

\tt \cfrac{1}{32}\left(-4\right)^5

Calculate exponents:- -4^5= -1024

\tt \cfrac{1}{32}\left(-1024\right)

Remove parentheses, apply rule:- \tt a\left(-b\right)=-ab

\tt-\frac{1}{32}\times \:1024

\tt \cfrac{1}{32}\times \cfrac{1024}{1}

Apply fraction rule:-

\tt -\cfrac{1\times \:1024}{32\times \:1}

\tt \cfrac{1024}{32}

Divide numbers:-

\tt -32

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

\tt -\cfrac{1}{32}\;\; \bf Answer

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That would be B.

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