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2 years ago

PLEASEE HELPP!!! What is the mistake in setting up the quadratic formula?

Mathematics

2 answers:

timama [110]2 years ago

7 0

Answer:

First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) . See examples of using the formula to solve a variety of equations.

aksik [14]2 years ago

6 0

That 6 should be -6

Let me solve it for you

$\\ \rm\rightarrowtail 2x-x-6=0$

$\\ \rm\rightarrowtail x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\\ \rm\rightarrowtail x=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(2)(-6)}}{2(2)}$

$\\ \rm\rightarrowtail x=\dfrac{1\pm \sqrt{1+48}}{4}$

$\\ \rm\rightarrowtail x=\dfrac{1\pm 7}{4}$

$\\ \rm\rightarrowtail x=\dfrac{8}{4}\:or\:\dfrac{-6}{4}$

$\\ \rm\rightarrowtail x=2\:or\:\dfrac{-3}{2}$

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blsea [12.9K]

Answer:

2. 3-(-2)-(+5)

⇒3-(-2)-(+5)= 3+2-(+5) = 5-(+5) = 5-5 = 0

3. -(-3-6)-(-4+8)

⇒ -(-9)-(-4+8) = 9-(-4+8) = 9-4 =5

4. -8-(-3-2)

⇒ -8-5=-13

5. -(-(-5))+7

⇒ -5+7 = 2

6. -(-(-8)+3)

⇒ -(11) = -11

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5 0

3 years ago

Et f(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 5)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 11 tha

nignag [31]

Since the surface is closed, and the vector field is rather complicated, you can use the divergence theorem. The flux of $\mathbf f(x,y,z)$ across $S$ is given by a surface integral, which the divergence theorem asserts is equivalent to a volume integral:

$\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV$

where $R$ denotes the space with boundary $S$ . We have

$\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial z\tan^{-1}(y^2)}{\partial x}+\dfrac{\partial z^3\ln(x^2+5)}{\partial y}+\dfrac{\partial z}{\partial z}=0+0+1=1$

So in fact the flux across $S$ happens to be equal (in magnitude) to the volume encased by $S$ .

$\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\int_{x=-3}^{x=3}\int_{y=-\sqrt{9-x^2}}^{y=\sqrt{9-x^2}}\int_{z=2}^{z=11-x^2-y^2}\mathrm dz\,\mathrm dy\,\mathrm dx$

Convert to cylindrical coordinates, setting

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta$

$\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{\zeta=2}^{\zeta=11-r^2}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=3}r(11-r^2-2)\,\mathrm dr$
$=\displaystyle2\pi\int_{r=0}^{r=3}(9r-r^3)\,\mathrm dr=\dfrac{81\pi}2$

8 0

3 years ago

Which graph represents the following system of inequalities.

Marta_Voda [28]

Answer: Graph C is correct

Step-by-step explanation:

The region below the dashed red line is y < 4/3x +2

The region below the solid purple line is y ≤ -1

The region below and left of the solid green line is y ≤ -3x

4 0

3 years ago

What is the amplitude of the function? 2. O 3 O 4 5