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Tema [17]
3 years ago
11

I didn’t understand how to solve this, i’d be happy if someone explained thank you

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer:

Option (E)

Step-by-step explanation:

\frac{a}{b}=\frac{c}{d}=k

\frac{a}{b}=k

b=\frac{a}{k} ------(1)

\frac{c}{d}=k

d=\frac{c}{k} -------(2)

Since, \frac{6a+24}{md+6b}=k

By substituting the values of b and d from equation (1) and (2),

\frac{6a+24}{\frac{mc}{k}+\frac{6a}{k}}=k

\frac{k(6a+24)}{6a+mc}=k

\frac{6a+24}{6a+mc}=1

6a + 24 = 6a + mc

mc = 24

m = \frac{24}{c}

Therefore, Option (E) will be the correct option.

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