To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.
To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.
Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.
Perimeter:
C= 3.14 x 20 m
C = 62.8 meters
62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter
Area:
A = 25 x 8
A = 200 square meters
A = 10 x 8
A = 80 square meters
A = 20 x 40
A = 800 square meters
A = 3.14 x 10^2
A = 314 square meters
Total Area: 314 + 800 + 80 + 200= 1394 square meters
12 problems = 30 minutes
24 problems = 60 minutes
36 problems= 90 minutes
48 problems = 120 minutes
60 problems = 150 minutes
Mary can respond 60 problems in 2 hours and 30 minutes/ 2 hours and half/ 150 minutes.
Hope this helps xx
assuming 
Then the column values for base five here are
5³ 5² 
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus = 
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219
Answer:
2
Step-by-step explanation:
-2y+10+2y-8
-2y+2y+10-8
10-8
2
